TA的每日心情 | 擦汗 2016-4-17 12:18 |
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签到天数: 1 天 [LV.1]炼气
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本帖最后由 tingsanguo 于 2014-5-2 14:01 编辑 4 d1 C" G8 R. R6 |
水风 发表于 2014-5-2 01:57 ) ?8 t7 t* k* D4 H. g
再次重温自己与数学天才们之间的差距有多大了。解出来了,我还看不懂思路 ... 9 X! e. p# h& x0 q; i( V" w
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fixed point f(X) = X = (1-n), where n is the number of people who divide the coconut.
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) r) L* P/ o: c( s' a) sThe least number of coconut before dividing is Z = [n^(n+1) + X], i.e., always divide (n+1) times." ]; w$ _/ T3 d* \' `
; h4 y. u2 q+ C& Q/ HAfter being divided (n+1) times, Z becomes 1, since X is fixed point.
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/ d7 d8 P8 g, F5 Y( n. J& in n^(n+1)+X, n^(n)+X, n^(n-1)+X, n^(n-2)+X
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, @+ ^2 q9 ]. h: B4 1021 253 61 13 1
( C9 U X- s1 N1 ]3 p, t5 15621 3121 621 121 21 1( B! _. Y9 H+ w- V6 x' R/ E
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