TA的每日心情 | 擦汗 2016-4-17 12:18 |
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签到天数: 1 天 [LV.1]炼气
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本帖最后由 tingsanguo 于 2014-5-2 14:01 编辑
- ? }% ^* q; Q; P水风 发表于 2014-5-2 01:57 $ t+ D* u9 Q) s
再次重温自己与数学天才们之间的差距有多大了。解出来了,我还看不懂思路 ...
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fixed point f(X) = X = (1-n), where n is the number of people who divide the coconut.- D- }* v6 s* i* R; l& y8 w, p
/ Z3 E+ c+ u4 c e; e# YThe least number of coconut before dividing is Z = [n^(n+1) + X], i.e., always divide (n+1) times.- ], _* h3 }2 d
& m8 V1 Z$ q& t. kAfter being divided (n+1) times, Z becomes 1, since X is fixed point.9 \3 x) `* Z. u* L1 e8 v9 c& j
( e/ [+ l" C; J9 qn n^(n+1)+X, n^(n)+X, n^(n-1)+X, n^(n-2)+X 3 O. _# {% o* z& \
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* ]8 w- X: D; q4 c$ v, H4 1021 253 61 13 1
9 J. X1 }/ |5 s3 e5 15621 3121 621 121 21 14 I7 d3 t8 X2 F
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