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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ; q& X5 C5 Y! G; a7 [4 P
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    解释的不错" A$ H0 V- e4 B/ z% T- \3 J0 B

    * k0 ]: t2 B. \递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    - L# _+ N/ O' k, M9 ^- x+ x7 U3 K6 c, q8 m8 B- `# u& \1 t) i1 M0 _: W
    关键要素
    % C+ q" Z1 t' c) U+ j  {+ L$ M1. **基线条件(Base Case)**
    ) [0 X7 K* h$ b! @4 r4 b   - 递归终止的条件,防止无限循环, }' k+ M; c* d! g' q  e+ g! L8 F
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1: Q' H2 V1 {  U) m8 I7 ~

    1 O( I' Z' N3 @9 x2. **递归条件(Recursive Case)**
    4 c+ E* e$ X) \1 K   - 将原问题分解为更小的子问题
    + L5 C4 m# E( ^6 J   - 例如:n! = n × (n-1)!
    . O5 G0 b. Q% d  _. U% b" Q7 Y* U
    6 K6 w2 ]  L( o6 G! C 经典示例:计算阶乘/ P7 @$ T0 ^7 n$ V: Y
    python
    " ^  u2 t  O6 N. R) x& ]def factorial(n):
      }1 Z& ?* }$ \" X    if n == 0:        # 基线条件5 o8 l$ m/ q$ {: @8 e
            return 1: m5 n9 ?1 i' |3 P
        else:             # 递归条件% \1 C+ Q6 F0 E6 b! g
            return n * factorial(n-1)8 }! C, _& l6 w6 h7 X8 D
    执行过程(以计算 3! 为例):
    ! d: T3 g$ h; ^factorial(3)  C' b$ X% u) E" U$ }2 v
    3 * factorial(2)* b3 [; i0 R- b# r& l
    3 * (2 * factorial(1))
    4 w- {) m# S7 I* \3 F3 * (2 * (1 * factorial(0)))  c- C. r7 A' k, _/ L( k9 z* d; z
    3 * (2 * (1 * 1)) = 6
    % J' E! R: _1 A0 O, g  A. U* n4 S, b4 U$ X
    递归思维要点0 l! G! V- j: Q2 }/ d
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑9 S: b, E) O- E6 W
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    5 [! Z( {% o; ]3 [& t9 |: w3. **递推过程**:不断向下分解问题(递)
    + j" B: r' O: H3 n( b6 Q% {4. **回溯过程**:组合子问题结果返回(归)
    ; `  a( C8 H( m+ U2 {6 \' x$ a, b
    5 W5 S- X' `. ?3 x 注意事项, X' P& ]: Y! p$ s
    必须要有终止条件( K2 {8 x3 O2 P9 m1 g+ L* G5 h
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    8 v  v( E( A+ l+ L某些问题用递归更直观(如树遍历),但效率可能不如迭代
    $ J% k: ?. Q% T1 i% ?8 S$ k尾递归优化可以提升效率(但Python不支持)
    2 v: u) f& Z% ]9 o
    / L& l8 ^' o% R( P! C0 l 递归 vs 迭代
    , F# O8 j3 \% _7 l' L8 w|          | 递归                          | 迭代               |2 `# u3 L+ r, Z: h! d
    |----------|-----------------------------|------------------|
    - x: `& u, f+ E$ S' k" I4 G7 b| 实现方式    | 函数自调用                        | 循环结构            |
    6 \* [# Z) g3 l1 x4 Z' B) L| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |$ z& E1 e+ E5 X& E
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    3 r% x9 K7 `+ d2 t| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    5 b3 D5 b9 }, l% {- r
    * r3 h3 X. L2 Y% _8 W1 \3 W 经典递归应用场景2 Y; Q' R; d! \+ l
    1. 文件系统遍历(目录树结构)
    ; H# r9 n7 M; ?) H( |2. 快速排序/归并排序算法' ^/ y3 C/ `9 J9 e6 g" D+ W" C
    3. 汉诺塔问题3 K5 n3 c( z* ]3 w. ?
    4. 二叉树遍历(前序/中序/后序)+ Z! Y* G: l1 N* ]
    5. 生成所有可能的组合(回溯算法)$ U9 |: i/ I9 V+ j3 n; S
    - u: N0 o, Q* B. B
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,, Z" k0 ]- |' R+ f* g6 u
    我推理机的核心算法应该是二叉树遍历的变种。3 Q, C8 h. q2 Z5 X$ y1 l$ ]; F
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    & ~6 n6 u' A+ m9 \; p/ i" A, @Key Idea of Recursion
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    6 A( a' S( y* y6 ~A recursive function solves a problem by:
    + f3 t, Z  J8 m1 @6 q& _0 V5 l. B( s& p, V
        Breaking the problem into smaller instances of the same problem.
      x+ `6 _& J, d
    $ Q4 ^( v. v) p+ E. @    Solving the smallest instance directly (base case).4 J- d6 m' W. B! p% }0 t$ _' G- o
    % h/ B& {( ?* S
        Combining the results of smaller instances to solve the larger problem.% w$ [  S8 y0 j. `% w+ w

    , ^7 t: h) v1 ~/ BComponents of a Recursive Function$ z) P7 s. N* j, \: M. p$ d
    6 N- K% N& Z3 Y3 m
        Base Case:
    & J8 V4 X$ z# R6 T6 S$ k
    2 h4 n. |  S% p" y) G; C7 _' T        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    & O$ N! E2 z4 B0 T- M
    ' n  c! L5 Q* [6 |; o4 N0 v        It acts as the stopping condition to prevent infinite recursion.
    1 G! p; A' {1 o
    : f6 S+ t3 ~0 ?" X0 j% k6 z        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    * G9 ^0 Q. _* N( h8 S
    & u' D( E+ Y$ W* {/ k" u% S: n2 `    Recursive Case:1 y' O. a: V; c

    8 f! s$ Y0 x2 D        This is where the function calls itself with a smaller or simpler version of the problem." d1 ~# F  b. ]
    ( |& ^( ]0 a8 c$ K7 M
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).2 C8 |" q7 u: I9 Q. b8 x2 `

    . }: T" R8 V4 d: ]4 Q5 c9 u" SExample: Factorial Calculation
    , h' \/ s! [2 }4 V. _) D! C7 D! w) A0 R2 S% j3 p
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    , `# X2 a1 }& f7 |% L* H4 T. X& U! d/ `' x9 _0 V
        Base case: 0! = 18 h1 H# f# \1 f& G+ L: J

    ! q5 `# q. J2 s6 u  b$ k    Recursive case: n! = n * (n-1)!
      P9 l; B5 R! T0 [& x% r$ A- g7 ?+ S# j4 g+ R$ k
    Here’s how it looks in code (Python):4 f  a) @5 U6 X* L# d( R1 q
    python
    : a, w5 S2 a( q% s2 D+ i
    : x4 [1 X) n- f8 _# B
    , g) r$ G7 P$ [0 Z) }- b) Kdef factorial(n):
    5 _1 h! k: Q# o/ H0 }    # Base case: r, z: e$ l2 @/ F; b+ y0 ]
        if n == 0:. K, z6 z( c4 u/ s3 x
            return 1* `4 O0 [% r+ G3 G+ u
        # Recursive case
    6 h" P: w/ n) }: r. O3 ]1 y8 X    else:
    2 |, [4 y9 S- w! m, [+ o1 O        return n * factorial(n - 1)
    7 e0 W* j) E* ~/ u# w+ O# \! [3 h* O1 e& X
    # Example usage4 w7 W7 \4 c+ Q- l2 A2 V) I+ q3 r
    print(factorial(5))  # Output: 120
    ) C9 f( C# k- J$ ?9 P* r& b% m+ V, [. C; W( b
    How Recursion Works  t- T# S' K  z0 X

    ( Z) W/ H! z7 J) I9 n/ ?    The function keeps calling itself with smaller inputs until it reaches the base case., k& Y* e0 r! {: m( m7 z

    , ]2 b3 h, O* ]    Once the base case is reached, the function starts returning values back up the call stack.
    ) g/ G) P$ y6 j7 D5 c9 u
    & Y4 L- v9 v( |* d/ u- F" |, T0 k    These returned values are combined to produce the final result.0 n9 t; d! ]; l, U+ t
    + X2 D4 h* l+ e# W3 N7 W
    For factorial(5):5 {$ v$ ]8 ]9 {9 s4 k" u+ m( T
    & g& Q  Y, v4 \/ e

    4 y' B4 O# ?9 h  j, h4 P% Sfactorial(5) = 5 * factorial(4)
    + Z0 }  ?* {5 h% dfactorial(4) = 4 * factorial(3)
    6 R( a# p, `2 r7 ^/ ?factorial(3) = 3 * factorial(2)0 ~+ i! Y7 q9 t
    factorial(2) = 2 * factorial(1)  F) E8 C! U7 L; Y( [  V: ]
    factorial(1) = 1 * factorial(0)1 K" J9 f  ?% g' K2 G2 X( n; U
    factorial(0) = 1  # Base case# K+ z) i% x2 F$ S% Y: u

    $ F" A% a4 ]6 w* UThen, the results are combined:
    ( c4 u( h" S/ }, W/ m, a8 z7 j+ j3 U2 \
    . I' [& d8 M( O+ g5 h
    factorial(1) = 1 * 1 = 1  V) w2 T, q  K. |" G7 G
    factorial(2) = 2 * 1 = 2: w* K3 l$ b3 f. W7 \
    factorial(3) = 3 * 2 = 6' D6 Z( P2 G6 g
    factorial(4) = 4 * 6 = 24
    6 f& c# y8 X; X9 r( d- v& Gfactorial(5) = 5 * 24 = 1209 S' s- i# Z" H6 d0 J

      [3 `  d  R4 h" A8 @Advantages of Recursion
    - j: H' P' d! h4 Z4 m: u; @; {. n2 g8 g" \, E' _
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).& W. E+ \- l% Y2 g

      d" Y& ?5 a+ `* u    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    : P- {2 m( X* l0 P6 {
    % \/ }! H0 I8 }1 U) y: IDisadvantages of Recursion
    % Z' w/ |3 h9 l+ B% s. b! p7 x$ n0 y4 U# o
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    % j5 e2 B) P7 W( A. b0 N7 @: F% P  w7 H6 m# f. d
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).2 {/ t, H1 f) G8 w
    7 ?3 Z% z. b( c- L2 G
    When to Use Recursion( h4 ]4 Z7 e: V4 }0 d2 s% Y
    9 A& p1 j6 D! N) P: `
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    7 D6 C) M0 M+ z8 N; ]& `+ X" |% v6 o1 E. b" n6 l
        Problems with a clear base case and recursive case.5 ^" l# B" D9 P
    . u; {& y- K# w" @. M& h$ m& g! ]
    Example: Fibonacci Sequence
    " N  Z/ z& i% ]3 e* W
    * W" w6 Q/ U. S) BThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:- {3 }" a( R; b0 h

    5 W7 g; L% Q$ F4 D    Base case: fib(0) = 0, fib(1) = 1, T9 a. D4 n4 F, v0 w- o; ^
    2 N) H8 P& P* j5 i
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    % D; N6 f& _. {) `! H1 P' Y" P) d
    python
    4 ^7 @& r  M6 Q7 H) I
    * u5 ^  m2 @8 x7 B5 I: b* {! s4 J4 @/ j3 @7 k/ [3 }; t
    def fibonacci(n):
    + A2 }& v2 J" J0 A1 i. J7 q    # Base cases
    . C' Q2 c! v$ a3 z* k9 {    if n == 0:
      q7 ^3 P6 g7 ?" y4 n        return 0
    - h' n5 D- Q: ~5 n# k: w3 E    elif n == 1:
    & q, q$ x3 d" s! A3 Q& |        return 1
    " s/ [% z8 y" r* A  u- n- s) b  A    # Recursive case5 H* r" X/ h0 B. Z
        else:
    3 f9 s& N- Q5 p/ A4 M( R" C        return fibonacci(n - 1) + fibonacci(n - 2)
    ( H3 ?* s5 E" r1 o& ]3 n* Q8 F. i. G; }+ E- X% T0 A# _/ F
    # Example usage
    $ |! T% n) H2 Z% S" E% }8 rprint(fibonacci(6))  # Output: 8  n+ m) B; n. o

    / i3 f7 X& i+ e) _7 u4 ETail Recursion# C" w& s" }0 I' g! q* t# B

    4 k. g- Z- A/ gTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    7 i. E$ Y; E; j  h- L$ _# ^8 a& d) Z( z0 E" b3 S2 y
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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