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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 7 i. ?# p& S8 [2 H: T! n: a( Z  u2 h
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    解释的不错
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    0 R. O  F) c5 I 关键要素- e7 h% t2 `! {" G( H* K9 n+ x
    1. **基线条件(Base Case)**7 B- g! c/ k5 Z7 _
       - 递归终止的条件,防止无限循环8 ^7 y$ s  v" D# `  k
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    9 b( d# _( ?% P; U& h
    9 R, V3 O" B7 A) c% r  B& w6 }! a- U2. **递归条件(Recursive Case)**
    7 y, o" i( A# c# C5 ^0 E   - 将原问题分解为更小的子问题
    " ?0 l/ \; e( l$ Z6 U& D: a" U   - 例如:n! = n × (n-1)!
    % E: v' \( K' g/ g7 x4 c* A: x! D
    3 D1 {- Z9 q8 s8 i8 O( L: Y 经典示例:计算阶乘) o, C3 z- K5 o! L. b
    python
    ; q1 }/ f% U) Y" O! Pdef factorial(n):4 @4 V0 \5 @- K
        if n == 0:        # 基线条件
    8 x6 Y  L( z$ r$ s; k( r        return 1
    ' G. [! O6 P% m' C    else:             # 递归条件
    ' q- F& j3 ^1 |" D/ D2 [        return n * factorial(n-1)
    * b) i' I$ U3 H# t$ `执行过程(以计算 3! 为例):
    5 n8 j5 ~2 X- dfactorial(3)
    & v. e5 T- N1 }! R/ Z3 * factorial(2)3 Y# l; @) C2 R# F; r
    3 * (2 * factorial(1))
    # b- g5 T" H7 G, k- h9 s; U3 * (2 * (1 * factorial(0)))
    ) L% q1 [% |$ I: n& z# {! l3 * (2 * (1 * 1)) = 6  V) D* n5 G; g4 b4 r7 y) v$ ^8 m9 y# J+ j

    ( s5 l9 t4 \+ ?2 T3 M 递归思维要点3 C; @, Z0 p  `1 S  b- q
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑' x6 S& s" o. a8 U
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)- @, a# ?0 V8 ~+ S# q6 Q* l1 b
    3. **递推过程**:不断向下分解问题(递)
    : u( T/ }. f% M/ e4. **回溯过程**:组合子问题结果返回(归)  t8 k- I# ?. x+ M/ V
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    注意事项
    1 n/ T2 E6 t, _3 F- F/ `: O  F/ C必须要有终止条件8 I% G2 A  {: i7 |0 N1 B/ q
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)! g6 A( k" C- T2 ^/ e
    某些问题用递归更直观(如树遍历),但效率可能不如迭代. Y! O. d9 h$ r* ]. @
    尾递归优化可以提升效率(但Python不支持)  p3 \3 A+ \/ N7 d' Q; L' n  q1 S

    ! o. u7 r' g5 `1 D 递归 vs 迭代8 ~4 _' x0 @  W3 W2 E
    |          | 递归                          | 迭代               |9 N9 X$ D2 ?0 N( g( r% {7 w3 B
    |----------|-----------------------------|------------------|1 @* {9 X  m% c1 u, y
    | 实现方式    | 函数自调用                        | 循环结构            |! g  S( D4 s8 C5 \0 u1 f% O
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    9 W" P) U9 g4 U| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    $ e  S  i& y% Y: b4 \| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    3 t5 v9 n+ _/ C0 K; i6 Z7 e  l5 |6 q2 V  |
    经典递归应用场景5 g0 W3 p/ F4 h  e7 f
    1. 文件系统遍历(目录树结构)4 a% V% \) v/ E- [$ A" {
    2. 快速排序/归并排序算法
    % v/ q8 [) B) C$ A$ L: b3. 汉诺塔问题6 s3 }" d) A6 A/ F
    4. 二叉树遍历(前序/中序/后序)( m+ ^+ N! d, R
    5. 生成所有可能的组合(回溯算法)
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    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
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    昨天 06:38
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
      |. o9 {$ }4 ?我推理机的核心算法应该是二叉树遍历的变种。
    # }) Y1 }: w8 W* ^另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    ' K& n- g  i$ Q: W' L5 N  U/ \Key Idea of Recursion7 m1 ~  d: J" U* b& P4 @4 c

    ) ]* c/ i$ P- I5 x6 ]4 j/ A* C! IA recursive function solves a problem by:$ P$ @9 R: ]1 G
    0 {4 q6 I+ N% h& N* P2 v
        Breaking the problem into smaller instances of the same problem., X4 |. l2 @' E& M0 D2 V' z2 x

    + K) `7 |; W3 g8 \7 `6 l- B: Y3 n% W    Solving the smallest instance directly (base case).2 ~9 G% R7 d& c% w1 g
    9 P! N9 F9 |0 ?" \1 Z: \" o9 }
        Combining the results of smaller instances to solve the larger problem.
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    : R  A8 J* L7 ^, V# j& C, jComponents of a Recursive Function+ N0 X1 @# X  Q( W" I$ a) o
    9 l" Y$ o0 F/ C
        Base Case:
    2 ]+ \  v5 ^9 ?5 `" m
    : f+ D2 t- r- A$ x        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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            It acts as the stopping condition to prevent infinite recursion.
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    # m7 x4 I7 g1 b6 n' P, M/ ]        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.7 G2 a, c0 o* y: l( l

    6 o3 E( Y: v6 I* I4 s    Recursive Case:) E; ]) p0 v6 ^0 O# r* J# }

    : x& M0 K7 d# _/ c        This is where the function calls itself with a smaller or simpler version of the problem.* W  m6 w. e! E% E
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            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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    Example: Factorial Calculation5 z% A3 @* i1 n4 b: {& a

    5 ~8 d0 Z& g8 rThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
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    ; h& i; m- W5 A    Base case: 0! = 1
    . l6 X' l& H0 f. t" W3 O4 _, g! p
        Recursive case: n! = n * (n-1)!
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    $ u: ]5 y$ d  ^7 h% d; I( QHere’s how it looks in code (Python):
    / |) ~* z, y8 V  \6 K0 Mpython7 ?1 m0 v; ?4 e: H. _$ j! R
    $ M! R3 F+ k" s6 Y0 D- y& L2 _( L/ z

    # a4 T# j, a$ C7 H5 Bdef factorial(n):
    8 }9 X  W0 U4 U( |* P; ~    # Base case; V$ P- R: F! }- k
        if n == 0:3 J7 w# o, s& I% h4 ~
            return 1
    / \% W! \  \* z    # Recursive case
    ; ?% q% X7 [- L0 k" v5 ]4 W7 M& r& B4 ~    else:
    4 X* e' p1 N: N( @/ w        return n * factorial(n - 1)
    . ~2 Z0 u: |4 w) U9 k" u' g5 z3 u/ n6 {
    # Example usage$ T3 b1 w7 h/ Z5 r: N
    print(factorial(5))  # Output: 120' z: N8 y) l9 `

    6 s1 g+ Z, ~5 vHow Recursion Works
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    ) _+ P0 j, j  f# w3 L    The function keeps calling itself with smaller inputs until it reaches the base case.  _0 Y6 R" e7 D; {  o. m

    + O% F# M, e+ l7 e2 p! ]- D4 z1 b    Once the base case is reached, the function starts returning values back up the call stack.
    + p% Q' U% G9 s% A9 U  f# \  H' L- h* b' a9 l5 a# T
        These returned values are combined to produce the final result.% m; _, _5 p  S! E9 T
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    For factorial(5):
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    5 {- \' @, [5 O
    . k' f& M/ t! t, l4 W' e0 O: ifactorial(5) = 5 * factorial(4)8 C5 J6 ]/ O" a1 I
    factorial(4) = 4 * factorial(3)
    % B' S2 z9 p' m9 Wfactorial(3) = 3 * factorial(2). ]5 \: o' g! O  ?0 ~" `" q, S
    factorial(2) = 2 * factorial(1)
    ; `: s' O0 I: b( t& T6 \factorial(1) = 1 * factorial(0)' V9 N) g2 M+ Y% L$ u9 K
    factorial(0) = 1  # Base case
    * o; i" C9 f6 l- K, H" i; ^3 Q* S$ \: H8 `
    Then, the results are combined:8 p9 b6 v# a; R! h- a+ ^$ V
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    & Z9 ~6 m* d- t$ s% A+ D  Qfactorial(1) = 1 * 1 = 1# t# o4 C5 t- U  M! S; r8 {
    factorial(2) = 2 * 1 = 20 _5 O3 n& i7 y2 W
    factorial(3) = 3 * 2 = 66 s2 g$ o& a, ^9 l
    factorial(4) = 4 * 6 = 24
    0 d! N) r6 R6 a+ A) y! M$ _& w  M6 kfactorial(5) = 5 * 24 = 120
    + j' u/ _3 X* l( i2 r9 o3 x. o, r6 J$ f7 R  B/ L
    Advantages of Recursion# }1 a. |/ j+ p  G
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        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).* W0 W) {' W3 c0 O  \& m3 b

    / D! Z3 c. c' p) a    Readability: Recursive code can be more readable and concise compared to iterative solutions.$ f7 L: K( I* L. y
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    Disadvantages of Recursion$ U1 f& c  D  s6 U
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        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.8 _' l* X) f) u4 b! l
    - Z3 ^% x9 F  t8 u: H
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    8 Q& Q8 I, ~1 m; j: m4 O/ W% H: F( ^( ^2 P5 m% y. k! W6 a1 D
    When to Use Recursion
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        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    % M, S' R1 V5 A; R, z4 n
    / X: X9 F% J$ r1 q& |8 K$ p; E$ n    Problems with a clear base case and recursive case.3 T1 J6 E7 T$ U2 x

    & b( h- `1 e$ G& L1 DExample: Fibonacci Sequence
    3 G; a. F  l" u! p2 P& d! e/ n3 ]+ |$ u
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    ; ^. c" S  A4 M% n4 K7 [7 p2 [& l3 w$ |7 D% n" [# @7 B. b
        Base case: fib(0) = 0, fib(1) = 1
    " Q% d  [; ^8 u+ e" g2 @5 Y7 e1 o% N1 h$ g& [: P) j; {6 o5 J
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    * q7 b5 x, H2 ~7 ^" o" V  C  X" K; O8 V: K3 z$ r
    python; ^! b) D: ]% y' {& x; i  s
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      I6 V& i6 ^8 j9 g$ F! g
    def fibonacci(n):
    5 e8 ^( M# N. ^  y; M    # Base cases
    3 H% k% c' j, i6 X8 {    if n == 0:1 N5 m5 E7 h. A& v+ d4 `) k9 z- B  z
            return 0
    / i7 S3 j4 d. m/ |. a. k    elif n == 1:! C2 Q+ u- T, e% F/ [: ~/ x
            return 1
    8 n" X% j% m" O1 c, _4 U$ q; [% c    # Recursive case
    " W! C$ Y  N0 Q6 f' C    else:
      B& Z8 @$ T9 t# b( T        return fibonacci(n - 1) + fibonacci(n - 2)
    % ~/ Y* R/ j+ g' j  d" e$ \$ J1 ~9 H+ Q$ L) p9 S0 ?
    # Example usage
    " H. b0 h3 {, s; ~5 ^7 R- A6 Z( P/ Bprint(fibonacci(6))  # Output: 8
    " I: R8 ^/ O) B8 A: \& E6 D
      t4 ~: K. R7 o+ s5 _Tail Recursion* L) R" X- z; l6 c
    ' u) O, f0 P2 d) q* I. m" B
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).* c1 x8 w" y  y5 T

    ; S3 g2 F1 i5 C5 Z& FIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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