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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 9 v0 I* P8 H9 E# {% \) [
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    解释的不错( i4 m4 L4 B" n* U. I
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    5 }( O  z# \; o+ x( G" i& K* I* x9 J& j" D" R
    关键要素
    7 u1 P  ?1 z$ r0 z1. **基线条件(Base Case)**- ?0 L2 T" t2 {+ f4 r: F
       - 递归终止的条件,防止无限循环
    . l/ W" a+ k1 N# |6 \( J   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    9 l) j0 ]/ a, N2 @# v* s  Z* E+ M: L- {) Q. ]1 j- r# O. I2 `
    2. **递归条件(Recursive Case)**
    % H& k, h0 {7 k$ G   - 将原问题分解为更小的子问题, X& ?+ ]% g0 P, `2 S# G
       - 例如:n! = n × (n-1)!
    % q& x+ O5 E# ^- e. b9 X
    5 L' A/ z0 G6 N4 Y4 ?! N  @3 a 经典示例:计算阶乘( a: ]) g/ X) \) U& S6 p8 A# m
    python- v2 ]2 A* ?+ K6 [7 j  r1 M
    def factorial(n):% A( Z. t, c$ y8 w& S# m* G9 N
        if n == 0:        # 基线条件: N5 g" m8 B6 |; U& P
            return 1
    7 I: V- [, ]& G    else:             # 递归条件
    + E/ y9 n/ K# C" @2 i        return n * factorial(n-1)
    & K, x- B' t" E& w9 H8 Z执行过程(以计算 3! 为例):+ n' A1 T$ W( |% K$ @
    factorial(3)
    & u( C' y' S( V) x3 * factorial(2)" v4 x1 T( l4 \/ |0 t
    3 * (2 * factorial(1))' @# L3 [% _1 r0 {7 R! z! m
    3 * (2 * (1 * factorial(0)))" s5 X2 L5 S! }6 @/ I
    3 * (2 * (1 * 1)) = 6
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    9 u3 x+ U# q$ G  R. a7 `4 D/ q 递归思维要点
    ' P+ N) b+ \* s8 K; }& n1. **信任递归**:假设子问题已经解决,专注当前层逻辑; [) r- C6 H8 O# r& y* i- v
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)+ c( m& l- k* N; O% Z
    3. **递推过程**:不断向下分解问题(递)2 w: y* _% R( W' }; r( b8 [
    4. **回溯过程**:组合子问题结果返回(归)+ Z1 p5 w+ K8 {+ Z

    $ e9 ?+ R$ z. f2 y, d% { 注意事项
    : u$ D, r% F" q8 f: R; M  p必须要有终止条件4 Z3 {/ N+ L# F* p/ P# r* z9 k
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    / t7 u5 m, f/ k5 k. a4 T, a0 v某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ! _4 e: V6 k2 a2 ^6 X1 s0 i( x( F尾递归优化可以提升效率(但Python不支持)
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    4 ]3 W* a6 g% m 递归 vs 迭代1 p% R% o: j( p$ _* h7 F4 g/ @" A
    |          | 递归                          | 迭代               |4 |  R, E# T5 {) s" q
    |----------|-----------------------------|------------------|
    ; ]/ x$ u2 `; x; b* Z2 a| 实现方式    | 函数自调用                        | 循环结构            |+ |( [- ~% B5 L6 k2 B
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |' l7 \6 h* G: K
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |/ H1 I, i  i! K4 P2 ]
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |! [: ^* u7 d! N! r3 S1 \* P2 r
    ' L- n+ E& `; L6 B
    经典递归应用场景7 o- V9 J$ ?4 e
    1. 文件系统遍历(目录树结构)  b# b7 H1 a. b# W" D$ K
    2. 快速排序/归并排序算法
    ' O4 u8 s) h5 g1 t, \3. 汉诺塔问题
    ' S" g/ N/ X. i) P( y4. 二叉树遍历(前序/中序/后序)
    ! ^: k0 N* C# X8 m. {# [5. 生成所有可能的组合(回溯算法)8 U7 R/ B* Z6 n+ C9 z
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    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    郁闷
    9 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    3 o% g, }5 a  h* j( p我推理机的核心算法应该是二叉树遍历的变种。" m5 q  a$ K( f  v. e
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:  l0 }: Y0 P0 h  U
    Key Idea of Recursion; W6 Q1 ]  Y& i0 ~
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    A recursive function solves a problem by:
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    ! _) B8 y$ Q( F6 |$ l4 _    Breaking the problem into smaller instances of the same problem.& ]1 F: _; q, T  [2 N
    ( m  H/ {/ z$ ]1 _7 b4 b1 D/ v
        Solving the smallest instance directly (base case).
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        Combining the results of smaller instances to solve the larger problem.. F' q. H, V* v+ A5 ^
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    Components of a Recursive Function
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        Base Case:; N9 Y; o: \, ?% W  ?0 c2 O4 O. G& d
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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    ( s- Y+ m6 @9 Z' @        It acts as the stopping condition to prevent infinite recursion., Z4 k+ D% A8 N: A- U

    5 r8 H3 V8 v8 d7 B/ ]% y2 B& P& [& O        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.6 m/ @- z& g- {4 r6 ?* A9 }
    - ~! F, X8 i4 e4 v. u2 }
        Recursive Case:" Q3 b* }1 }# C" y+ e
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            This is where the function calls itself with a smaller or simpler version of the problem.
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    5 j, E3 U: o. Q6 W        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).5 @2 h3 d* O7 b# Q
    + O( w) R5 g! L
    Example: Factorial Calculation
    / l9 d1 @: r4 o; p( U: Q0 X% G' j/ Z7 g. o  t
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
      I" q6 N3 r( d! \
    - k  S+ Q* l( `6 C* `/ d    Base case: 0! = 1
    % _4 m( `2 f! ?' ^: A0 k
    ' c. W; t  W, j8 m- E& u2 e/ O    Recursive case: n! = n * (n-1)!
    ; u, ^4 Q$ _7 E! q( r7 A( }% Z1 q& K
    Here’s how it looks in code (Python):
    . o- s  B" i5 `8 y  U8 `python3 }7 u% {1 k/ b

    8 n' }) I" M* V; }+ k% @& _: g6 B: \- @1 N5 m" I
    def factorial(n):
    4 v0 q* ~. z; A4 f0 B9 X, `$ W7 T$ I    # Base case3 ?/ K( f. V/ Y6 j" z1 Z) m  b
        if n == 0:7 n7 H6 ^8 `4 o' y
            return 1
    , Z8 @5 k, |! i/ @. u. w; n* H    # Recursive case: ?% J8 X0 {. t  e" K! [7 g/ |& ]
        else:( I: p# J" r" }  x1 c
            return n * factorial(n - 1)& j, O8 u; }. B
    ) F, n5 L! W( u6 e3 i1 v, ^
    # Example usage7 F8 A) g3 H1 U9 Q+ ?- ~
    print(factorial(5))  # Output: 120
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    How Recursion Works
      ]4 @: r7 g, j4 b* Q& l
      Y6 D* ?7 X* N3 N2 R1 N$ u    The function keeps calling itself with smaller inputs until it reaches the base case.
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        Once the base case is reached, the function starts returning values back up the call stack.
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    . J7 }$ [; w" O7 O1 ~6 a    These returned values are combined to produce the final result.6 z( N7 ~  g4 F; _0 f
    6 |$ ]' C' m! F9 X
    For factorial(5):
    " Q1 O0 D  b% s7 Z$ O  m2 [% L, S1 Q5 Y

    & `' z# O, S' W' dfactorial(5) = 5 * factorial(4)0 y8 J0 |) Z# P; o
    factorial(4) = 4 * factorial(3)% O3 S' s0 T% |) q9 I. ]
    factorial(3) = 3 * factorial(2)
    & a" ^$ W! N& t7 r6 p5 S) ufactorial(2) = 2 * factorial(1)8 I& Q' m3 _3 Z6 X# D! r
    factorial(1) = 1 * factorial(0): p- i0 v% F' x* ~0 N9 A5 J
    factorial(0) = 1  # Base case) ?! S3 i+ L! m5 Z3 I: ?
    . l1 f, |+ k: F( e1 x" W7 P3 H; G! @
    Then, the results are combined:
    : _  O0 q7 X* h: n! f+ {, L5 M5 a# E' C
    9 y3 ^: P! \- g8 d+ P) h+ Z& O5 q/ ?
    factorial(1) = 1 * 1 = 18 ]2 d. H; C% ^# C$ O
    factorial(2) = 2 * 1 = 2
    / N5 R+ K' d0 `, Gfactorial(3) = 3 * 2 = 6
    1 E+ w- v/ l" |5 u; p2 vfactorial(4) = 4 * 6 = 247 X0 U, z% I* x. [. ~
    factorial(5) = 5 * 24 = 120- ]& n2 T& m8 }$ Z) }# {$ I& H

    : ?" m6 r+ o) R' @1 J! uAdvantages of Recursion
    3 B3 |: h* ]8 u& U
    , e/ l# `4 v$ c    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).& a( S2 w" M  x" |

    + ?6 d" _% {. J" o0 q$ E5 @- |/ y    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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    & B7 w6 ~1 c) ?7 ^0 ~6 \0 lDisadvantages of Recursion
    4 s5 R; l* U7 _
    ( q" Y9 b: {3 V. j6 y* \0 S    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    8 ?- q0 v  \3 H
    + q1 q1 B! C/ m7 Z    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).' [+ l# L: ]' V# A3 h1 v( W! V& f1 c
    ' A. |: h) H3 s, N* c
    When to Use Recursion
    % R1 v3 X1 j* S: E; u* ^: {1 G+ m4 |* u4 A4 `7 O/ ^
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    + R) e# R; X6 [% E5 y, c. ]  Q: i+ K! W' m( |3 D
        Problems with a clear base case and recursive case.7 X, k- c- T' U. T$ k) T$ s
    ! S' p5 d5 L3 x! T) T& T
    Example: Fibonacci Sequence5 B' O$ p, k1 }3 {$ j
    4 q' x; `4 @' o5 _
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    % U" L; B$ ?* u+ y5 ~8 ?3 G9 b
    ; C% m: w. E" }, J    Base case: fib(0) = 0, fib(1) = 1
    ) n  t1 Q7 K+ G7 R. Y$ V0 Y
    . P/ H$ T  p) |5 l$ o  H    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    ; L6 W/ @- Y1 e% k# b6 E4 N# M, D5 r; ?' F' O& V
    python
    2 L8 R, q: _, F3 }( i5 H5 ?' N9 H" n" t# F

    8 o8 Z2 O) G9 c9 F# Kdef fibonacci(n):
    , I8 Q3 _- N4 j7 G* s; @    # Base cases
    9 c2 a3 _: c/ c/ X9 u) k2 x    if n == 0:; |/ \, _! i2 ~9 e6 @) D$ Q6 S
            return 07 N, m8 S1 k7 K' k
        elif n == 1:2 W! G3 @1 \6 U4 w/ \) \
            return 1
    9 r% T- |  K: e( q* O; K0 G% i3 ^; @    # Recursive case
    1 D) j) H+ {3 F) }# _5 d  N    else:
    " o/ S. z6 ]7 l) ?" i8 c7 K6 k% [        return fibonacci(n - 1) + fibonacci(n - 2)
    8 I7 f$ P+ N+ ]7 n6 L; h
    $ Z7 c9 X" K% R9 p2 ]( ?2 I5 {# Example usage
    : ^% d1 D( S. x# s3 q) O+ yprint(fibonacci(6))  # Output: 8
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    Tail Recursion, }7 I# v; E! t. o8 P" T

    0 }' N8 T6 k( e8 V% rTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).4 U- e! P1 M/ }$ @5 g
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    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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