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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    5 H6 y! a& j- S, t* _/ y& v0 w4 v& {" s; _, L$ }0 H
    解释的不错
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    关键要素9 L# D9 ?( K. N
    1. **基线条件(Base Case)**/ x& ~/ L$ S9 q
       - 递归终止的条件,防止无限循环
    ; h8 @0 U" ]8 E* ?8 w5 M   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 17 \/ u* h$ Y9 x4 Z3 E* ~" t
    2 C$ t8 D" c8 a/ v
    2. **递归条件(Recursive Case)**4 N: L5 e2 L4 E
       - 将原问题分解为更小的子问题
    4 `/ \, Y, Y  j# [! N7 r   - 例如:n! = n × (n-1)!* L: J, |1 b, W; }# [" b
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    经典示例:计算阶乘+ `, ?0 m1 d7 |+ I5 C
    python
    ; R1 U) ^8 F( m4 u' U. Vdef factorial(n):" `1 V# ~5 f  w0 v5 ~, y1 Y. h
        if n == 0:        # 基线条件: P5 Y9 H0 G2 l* m3 ?
            return 1
    ; x7 V3 C5 \* e0 j    else:             # 递归条件3 F8 S% J5 P  e( Q( C1 J# e
            return n * factorial(n-1)! J5 @; g1 H( |# l
    执行过程(以计算 3! 为例):
    1 }3 ~+ Q2 F  E' C; H# N, Sfactorial(3)
    , P9 V* p$ ^* @8 @3 * factorial(2)
    / C: l0 ]. R: K- e3 * (2 * factorial(1))( b& r- [0 G2 Z* ]
    3 * (2 * (1 * factorial(0))); F; f/ ^; c) h$ b' J9 N
    3 * (2 * (1 * 1)) = 6* L. O9 b, C, k: X' U& }. k3 c: c

    / r5 [2 R2 j# m! I$ g* S 递归思维要点) v, R! t! S$ J( ^
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑( N5 @5 y7 B# J
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)3 e& w! ~5 y' \0 s$ H
    3. **递推过程**:不断向下分解问题(递)4 x) T! d# K& F9 q5 S) T4 |
    4. **回溯过程**:组合子问题结果返回(归)
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    ) G: \  `5 f* ?5 Q" ]; I 注意事项2 a* ]- {! ~1 O3 {# O) m
    必须要有终止条件& D) T# c& J4 o0 Q* _1 s
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    - o9 S5 L+ T7 j. U! }; b# M某些问题用递归更直观(如树遍历),但效率可能不如迭代
    . K0 L& ]" g+ O3 d" l; a尾递归优化可以提升效率(但Python不支持)
    3 Z0 c: B) Q8 i( o) ^1 h7 F; B# O* b4 W. }5 c( q
    递归 vs 迭代
    ' ]7 d: V' l" C) m; Q|          | 递归                          | 迭代               |
    ' h% G, l' D9 L' X! M8 \|----------|-----------------------------|------------------|. m+ T1 O, P8 `, k+ t2 B% Z* V
    | 实现方式    | 函数自调用                        | 循环结构            |3 u/ F9 |8 Q  ]: ]
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |! v+ M8 Q7 l# S  {* ~
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    5 P0 E$ M4 S# U# ?| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |9 l  B& w4 H% v* w. P* h  _
    + x7 d- x* c8 @2 I
    经典递归应用场景4 q7 J  l9 V; J
    1. 文件系统遍历(目录树结构)" S9 l2 o" |) P; j/ x0 r
    2. 快速排序/归并排序算法
    ) C1 h6 s; V! d: x: _7 s3. 汉诺塔问题
    : r  a% i* h2 L9 s4. 二叉树遍历(前序/中序/后序)
    1 l8 \: k( D0 t6 r% U) b5. 生成所有可能的组合(回溯算法)
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    ! M9 E% l/ t" U9 K4 P  X. T试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    昨天 06:38
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,( ]4 P6 H* n% ]0 h' ^% Q
    我推理机的核心算法应该是二叉树遍历的变种。0 w) w$ S: t  t, n0 q0 z, j  _
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    7 F( K0 `; {8 }6 E; VKey Idea of Recursion& g4 \$ U) X" U$ |/ @
    - w( a  J, ?3 ~$ c# a
    A recursive function solves a problem by:
      m1 S  m+ |" V6 R) C* f* Q7 L% Z( m6 N+ U1 ^4 D+ }% W& W; y3 o9 w
        Breaking the problem into smaller instances of the same problem.
    . ?6 q: c% U* |, V( i: i, {( _6 v& X' u' {0 N& L
        Solving the smallest instance directly (base case).
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    + v! @) N0 p2 e. w+ n" a  }; k    Combining the results of smaller instances to solve the larger problem.( g3 G) q8 g# P. P

    " ^& N8 S/ W# ~+ u, {Components of a Recursive Function% k( l- i& u8 Z, n+ y( m+ C
    8 e  h: l8 q" _& K
        Base Case:
    $ @( z) b' h1 P& c. w8 ~
    9 c( A) c7 Q7 N) C/ C2 [        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    6 ^7 `7 C5 U2 V* |) U' g" H5 k6 k/ z1 c& S4 Y
            It acts as the stopping condition to prevent infinite recursion.
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            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.# _5 O; r9 Z4 M8 X) c: p- y9 [

    , ^' b) ]+ a5 A; e    Recursive Case:0 H0 Y4 Z$ Y" I# Q

    1 a% p1 Y3 W/ b" V/ \) {; g% R        This is where the function calls itself with a smaller or simpler version of the problem.
    ) }( V8 A) M! G# V7 i3 p+ {: w- k+ L0 b% S) B, m) }- Y2 g
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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    0 _4 ^. Y/ y" q$ {1 Z* qExample: Factorial Calculation$ X4 ^' V( [8 O- Q9 _
    ! U+ m" r  G$ b/ P# @
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:+ Y' X6 [, Z5 S8 r

    8 |' X% }  Q8 L5 T& j3 }    Base case: 0! = 18 Y4 {+ r" y8 b7 N! g3 |
    ) i" p% w( M8 ]: u4 `, ?3 u
        Recursive case: n! = n * (n-1)!
    ( p& C% W! ?, @  Q8 b# o  c) e- _$ V
    Here’s how it looks in code (Python):" x6 o) F/ k- T( F
    python4 m9 s0 w% t3 [. O: m6 b3 Z

    6 f* P; X3 V. k" ?/ j; I6 H6 _
    $ q/ o3 C" d$ T. Sdef factorial(n):
    5 R  x7 }0 }. ]. d% ~4 ~$ i5 K0 ^/ ^    # Base case
    6 H( O- p0 T, R& _    if n == 0:- a4 A2 [: m& Z( G2 R- x
            return 1
    + t! n$ K8 M6 b8 J$ Z' T: N    # Recursive case# c" i% e% G# c
        else:+ ~! B5 B+ W1 J6 o5 t
            return n * factorial(n - 1)
    + C& i1 e1 n( K, Q5 x* B9 h& W' Y0 ]9 U
    # Example usage* F. B6 j' P6 J' ~8 e# ~8 t, c; x
    print(factorial(5))  # Output: 120- u4 D3 W- D% F& P$ I

    - B4 m0 l  b' u$ k7 J3 i( a4 ~How Recursion Works
    : m5 I  f6 n2 X3 \& M( ^
    6 Y4 l6 k/ K& ^$ D; Q0 r  c2 o    The function keeps calling itself with smaller inputs until it reaches the base case." E1 @  r* Z! |3 O: {; J# r
    ) l$ M( j9 A* F2 u8 U# Z
        Once the base case is reached, the function starts returning values back up the call stack.1 ]. N6 A" E" b
    ) u& i3 W# G8 `0 A0 @; Y; O) I8 B
        These returned values are combined to produce the final result.. q: c: v8 X) x
    * E1 F8 p( ~5 n* o
    For factorial(5):
    ! x  i0 u, g; z- G2 v/ ~; p% \$ F6 ~

    # k; T+ [6 T9 m6 P4 O7 Ufactorial(5) = 5 * factorial(4)# i7 Y' |( F1 L, H! _7 _/ W
    factorial(4) = 4 * factorial(3)9 [  ~: t4 U* U% z. v, a
    factorial(3) = 3 * factorial(2)
    : f* P& V+ \8 o! Efactorial(2) = 2 * factorial(1)! E8 Q. @( ~9 a. C! M, ^7 l
    factorial(1) = 1 * factorial(0)
    . N! O% l$ N' ?* E3 Afactorial(0) = 1  # Base case( z. I5 w0 w3 r- w" C) w
    4 Y$ E/ {( z3 M+ v6 B
    Then, the results are combined:
    / I, u0 U5 _" m& n/ \
    , q& M( T6 y! j9 |7 {: r9 ]% R) a& F
    factorial(1) = 1 * 1 = 14 @  J' M. T2 r4 q. J1 H" S
    factorial(2) = 2 * 1 = 2
    - E5 ]. f: v" b! Vfactorial(3) = 3 * 2 = 6
    4 j8 B+ O4 t( }4 c1 _* ^$ ]factorial(4) = 4 * 6 = 24
    1 ?/ v% h6 W% X! Q7 Hfactorial(5) = 5 * 24 = 1208 @. v# T. k9 s  Q6 k! {. b
    & |) G% u' c" D
    Advantages of Recursion
    & Z" [( O$ O) s$ r2 j+ |2 X
    - y3 n6 N% \0 k# D2 j: [3 T8 [2 M4 {    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    # k# f/ P8 G( E2 _; `' o
    3 n/ a- m& J# v9 R7 a" u    Readability: Recursive code can be more readable and concise compared to iterative solutions.) b7 v4 g  X9 N. j4 T
    2 t/ n) @+ A6 {, o
    Disadvantages of Recursion# S4 X8 e7 a- z& X, D7 L- m! o

    % a5 g2 t3 X) L* @    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    - w# B$ ^+ n4 [) l& U) O0 s/ o
    + F  L+ C- t8 v) _; [" w) ~  \2 Y    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).0 P4 \% f# z7 U+ c* f0 a0 h, J
    9 Y8 _! o  q+ y' a, E# B0 x
    When to Use Recursion% o; E0 P- A# y4 V. f

    / {8 f  |) j0 O% [! ~2 `% V    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).! P2 n! _0 p6 L: C2 i* i4 f
    ) `% J( ^1 o; V$ t
        Problems with a clear base case and recursive case.. o3 _) b9 B* p+ E# h

    ) O8 \2 E5 X, z7 K' s! z$ oExample: Fibonacci Sequence; X: }/ P7 [9 f1 X

    * m" X, q7 z" B  q: dThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    . G: W- [( z) K  z; Y9 D7 k7 u# C1 }0 D4 R' H; U" e
        Base case: fib(0) = 0, fib(1) = 1
    ; t- n- c9 s7 i7 c
    6 `! P6 Y- T9 y: e, i- x    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    8 t9 D2 @1 B$ ]2 P7 A+ i" h- f" f4 n  [+ j+ [3 V
    python; z. @) y# k3 ?& ?4 @, N% y4 Z

    6 ?! t2 ^4 n- |$ p
    4 y# e$ Q! V3 d" h2 P* qdef fibonacci(n):
    ) X0 I  ?3 b. I0 a/ J# n    # Base cases6 Y- i* x3 ?  @% w, N* f
        if n == 0:
    ' o# L9 F& ]5 d  _9 d! R* u        return 0
    8 D) }; z) x. _; d, q2 r9 f    elif n == 1:
    4 S+ n' M; z& e/ b4 v        return 1& Q* s: N( A; F
        # Recursive case! {9 ~- s, N# A  E
        else:0 e. L4 r; v' Q, _
            return fibonacci(n - 1) + fibonacci(n - 2)' A8 t( x" D8 w1 g) O

    * N. w2 M% }- [# Example usage" Z* I1 {) Q/ x& v
    print(fibonacci(6))  # Output: 8
    , F' P' R2 I* g, T- _( K6 N& q
    & ~. x0 a) D3 i/ N2 XTail Recursion
    6 `& U+ q4 \  t8 w; C7 k* j, O9 V) c( O1 \
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    1 E0 T: \  Q% @5 z/ J4 M* m8 @4 k! K! m4 _, J
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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