设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2929|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    + O! G1 U) j: I( f6 B
    4 l" l' \9 r0 q: @5 J: x# S6 i. z解释的不错
    1 T6 @( g& v- @; e
    : A( K8 p* I) y1 \3 C/ Y6 B5 {递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。+ p% T: G$ ]' H5 Y$ h

    1 _' [- f3 D5 ?5 ~/ D# _" v# _+ G2 t 关键要素
    4 V$ B2 m$ V9 m: G1. **基线条件(Base Case)**. p+ ], I( ^* J0 [( a' A& I3 I8 [
       - 递归终止的条件,防止无限循环
    % `+ C& [- t& E/ _3 S) m9 M3 \9 j   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1; ^# ]8 c7 ~& X6 D2 T

    - e+ U) E2 ?$ K, D1 r" Y* l9 z2. **递归条件(Recursive Case)**
    , |9 f7 b1 f" B4 x( h3 y* Y   - 将原问题分解为更小的子问题
      S, D" `, ^# ~: f: u; C# Q& @   - 例如:n! = n × (n-1)!- v" h: W% [; `1 U3 c

    ( l; M$ `/ d$ _; y 经典示例:计算阶乘
    6 Y- G6 E- \. G( z" apython  k5 [, Y- V  ~0 {9 M
    def factorial(n):
    7 b# a- I3 C/ K; K& M* G" z6 l    if n == 0:        # 基线条件' q, u5 A$ l  p( |% S6 N5 u8 O
            return 1
    % o: ?- j( f3 T8 y8 J" A& d# q    else:             # 递归条件7 ?% ]- ~% S# t8 j* q0 J* e2 U
            return n * factorial(n-1)
    - T. R. l& ~, I- \. L& e: l4 ?执行过程(以计算 3! 为例):$ B% G7 i- k% y/ T; r. r
    factorial(3)0 A6 @; a8 o/ w5 h- k
    3 * factorial(2), X7 A  ]( f' ~! ?
    3 * (2 * factorial(1))
      D4 O5 K, F$ Z0 s% p# r  N3 * (2 * (1 * factorial(0)))3 |$ J# M& Y9 e) @; W0 N) }5 m! s
    3 * (2 * (1 * 1)) = 6% {; N6 h2 C! z# r
    ( F! e& \% \4 E' c
    递归思维要点
    2 N7 `: l0 H! \( T* ?& j1. **信任递归**:假设子问题已经解决,专注当前层逻辑9 U: y  O" ]$ D
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    3 z2 q# y: L# N) [0 O3. **递推过程**:不断向下分解问题(递)2 p2 @. N% J' m5 W% z' f  d
    4. **回溯过程**:组合子问题结果返回(归)
    5 ^" x+ w1 M' V3 U9 w3 t+ K3 ^
    0 @6 |' n1 K) Y& V 注意事项
    , [+ w: ]" r4 |  J必须要有终止条件
    8 m, q! b* T& X$ w, J递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    8 h9 |% \' `4 k, d  U某些问题用递归更直观(如树遍历),但效率可能不如迭代9 d. X7 \8 A; w! b0 u3 e- Y5 A
    尾递归优化可以提升效率(但Python不支持)
    7 o4 m1 V% V; m( P) t/ ~- T' H8 o6 u. p. }
    递归 vs 迭代
    $ V2 U+ z8 z( ^* E$ R% V|          | 递归                          | 迭代               |6 Z* A- [+ {* {% h2 V% s
    |----------|-----------------------------|------------------|
      @* c5 p( d8 v0 H: Z9 f  h| 实现方式    | 函数自调用                        | 循环结构            |3 k+ s" o8 @1 N- C: |7 _7 ]
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |. b5 H+ v# ]5 e9 ?  ^! m7 f
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    ; J9 }9 \# t6 v- W. t. ^0 \| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    * {2 a& A; f! q% i/ m& M( L# D) q' z: s  p8 S, p. ^8 T& @
    经典递归应用场景' J; S8 Y: U/ n4 H0 r
    1. 文件系统遍历(目录树结构)
    % G; O1 ]" B% s) K2. 快速排序/归并排序算法
    9 A0 t. Y0 A$ ]  b( h( X7 o3. 汉诺塔问题; Z) S% `( E1 `2 X0 d$ D
    4. 二叉树遍历(前序/中序/后序), V6 X3 n% K* w: A$ ?
    5. 生成所有可能的组合(回溯算法)
    " c7 e( j$ n/ G5 [. M/ t( G( {! y+ P8 s
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    奋斗
    昨天 08:56
  • 签到天数: 3281 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,9 V/ g  y; Z1 k0 K1 U0 ^) [
    我推理机的核心算法应该是二叉树遍历的变种。
    ' J$ q" h- M9 T6 _2 @& b, P* z5 Z另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:! r: z! v0 v* B6 B% d2 b3 v) u
    Key Idea of Recursion; L3 c+ Y7 i- M' F! W
    / F- Y  k* n7 K7 o1 G6 ~
    A recursive function solves a problem by:- |7 d' L/ D0 I5 o' S! J$ p6 `
    8 |) v9 d4 P2 X; k5 I
        Breaking the problem into smaller instances of the same problem.
    & `! u7 L6 {, `( ~& e' }* u
    0 @5 S# A# e& D7 b    Solving the smallest instance directly (base case).
    # r& f+ C  w/ B& x: \; ]/ y; w: I& Y/ h+ r: O3 q
        Combining the results of smaller instances to solve the larger problem.' V) }0 y* g$ V$ E5 {
    6 C6 F9 H1 d; d% V( M
    Components of a Recursive Function+ R2 J& Y0 |) ^
    ( y' }4 J; H; t& `, A6 k" e
        Base Case:
    $ _* m  j0 ]- n. }! _0 m+ g# @5 _, `- ?
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    8 r! n8 V$ S: `! Z2 Q. f
    1 X# e; Q  g8 V" w# v, ?" t        It acts as the stopping condition to prevent infinite recursion.4 R* A" d) b) |5 e7 ~) G

    - O- e; j. ]- Q( j' j  E+ R        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.7 b1 o. y" S( \' s" D* s. t3 D4 Y

    & w8 Y. F/ E; _0 c" |    Recursive Case:
    + a# q. x6 v) n9 w5 l/ N
    " W& [4 P5 y5 H2 A. d' w4 u! ?        This is where the function calls itself with a smaller or simpler version of the problem.
    7 N1 Q5 b8 z& C, l" [- l7 L3 c2 i7 L" Q" w5 X
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    8 B4 a2 ]2 [3 A! r
    % b# H- L; x- uExample: Factorial Calculation
    2 k- C7 D( x) ~  L
    3 B+ ^8 G: z5 m. L) J+ Y" `The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    8 |+ z# c3 c6 |1 ^! @
    $ ]/ {4 ?0 h' _; q2 L& U    Base case: 0! = 1
    + O, w4 {$ Z& k( {" p" c/ |
    # Q' f4 ^9 v% b* a, N6 Y    Recursive case: n! = n * (n-1)!
    5 n7 i3 G$ R1 u7 l" u/ X, O! x8 k9 J3 `9 t' L( U
    Here’s how it looks in code (Python):" i: t5 f* r8 j8 S9 K+ \0 ?* t
    python- P! T" }; g( ?# t& ^

    % ?7 y; I* [1 n# F# y1 u& P, _" q+ ?, N3 H/ f6 y) l! X) |
    def factorial(n):( ?, F& t! X' }" _- h
        # Base case6 c+ a, r/ n/ Z5 Q5 _2 n" [% I
        if n == 0:
    7 L' A" r6 [- s& |, M        return 1
    4 @) A. d5 K( Z+ {    # Recursive case
    1 S. A5 F; v, V& F3 v    else:
    9 q- h6 {( n5 s# u) C$ C1 B  z        return n * factorial(n - 1). f/ E2 _4 e0 v2 ]6 m

    , Y4 y- i0 `, Y3 }% h* W# Example usage& ~/ p( X, e+ v/ \& D
    print(factorial(5))  # Output: 120
    , v3 f7 [9 d. T6 N- k$ E. J' u+ V2 O3 a' j% _
    How Recursion Works9 r4 [/ d, a9 G+ |1 m+ H) U2 H

    ' q5 K: D# B2 G9 k    The function keeps calling itself with smaller inputs until it reaches the base case.
    - W- [% G- m6 P" w6 c: H1 I1 G4 Y$ w" x# h) @, O1 h
        Once the base case is reached, the function starts returning values back up the call stack.
    , f: N; L9 K( I& I0 B
    7 h- w& A+ y+ o: X& z    These returned values are combined to produce the final result.* v  ]2 j( h+ u, A" U, y
    4 V) s: o0 T" d  t
    For factorial(5):% L' t( w$ ?5 W+ g8 Q& b1 f
    ! [, Q0 v& w, l" K

    2 L6 z. Z4 P& _. n4 afactorial(5) = 5 * factorial(4)
    , h& z2 E2 R. V" ?0 v0 R& lfactorial(4) = 4 * factorial(3)# ^$ U% i& h! j7 M
    factorial(3) = 3 * factorial(2)& i8 r( ?7 [. J8 V* }
    factorial(2) = 2 * factorial(1)
    ' F& p  m9 u0 e8 J8 Y6 {* lfactorial(1) = 1 * factorial(0)
    + k9 A* F$ A8 A% @( f' H: c* E/ U" Zfactorial(0) = 1  # Base case
    4 R0 }3 Y1 H) Y
    5 C/ d: t2 n: g5 oThen, the results are combined:
    % W# Z7 ~1 s& K( n4 R! @3 U
    . v$ f. s! V4 ?- o; a# U
    / [6 @) D1 M) [" H9 `factorial(1) = 1 * 1 = 1
    0 U; J6 R$ C9 _factorial(2) = 2 * 1 = 2
    1 g, E" L; ]+ _; p1 G1 Kfactorial(3) = 3 * 2 = 6( Z: n8 z% y$ ^$ Y
    factorial(4) = 4 * 6 = 24+ v8 f: {. u! C- O- v0 F& h2 p
    factorial(5) = 5 * 24 = 120  Z6 Z( q- D9 g
    # T- ^* D5 [. s* f. X
    Advantages of Recursion
    5 O; f: C7 F4 g  E0 R) y+ O+ ?
    ' k  Q5 s# d5 X    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    / d- r& k1 I( K
    " [) ]. U# i9 J! @0 Y; K. y( U  H2 A    Readability: Recursive code can be more readable and concise compared to iterative solutions.3 A5 q3 w; B0 a# @

    + @5 O/ \  M" \: I6 E0 LDisadvantages of Recursion
    " O; O3 t' g( q- [2 w: q) k, b, O  P0 y4 n6 M  k6 h5 O# Y
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.  b; p: H. U4 p- M7 ~5 I

    1 C" c0 Y2 A6 G1 H5 @  E* @    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
      D* g8 K  D0 |# a4 K4 E. Q) b+ z$ \; c; V
    When to Use Recursion
    2 M) L& p/ Y# G, x( [) s  c, |
    9 y  M5 U3 `% E& c9 w9 S    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).8 p% \& h/ ^+ x* _- b0 C9 e% m
    9 C; V* z; |( I" I: H
        Problems with a clear base case and recursive case.
    8 `8 L6 o5 y, C* h+ M5 D6 x  ^# X( h7 C. R
    Example: Fibonacci Sequence% U" Z- `8 G! f. L3 u! ?

    5 c& `2 ~. X5 l! jThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:9 \' X' d' @3 }

    4 u3 R/ A$ V, _1 n2 O    Base case: fib(0) = 0, fib(1) = 1
    6 V) F1 O1 @9 @! [$ a, ?! i6 n
    4 V: V! k8 \* s3 |. v# X5 F7 Y- U0 w    Recursive case: fib(n) = fib(n-1) + fib(n-2), s$ W# M/ S& G; ]$ F
    $ v/ c- A" v0 B! ]
    python
    , Z/ @5 M. \9 c
    7 R' F3 I, Q- Z; e
    ) [. `1 S; M! `* X( odef fibonacci(n):
    - ^4 y# @* U& s% M: k2 ~8 Q    # Base cases7 P, \! m+ g9 V& L1 Z
        if n == 0:- v( q" ^+ n8 k- D3 Z& N
            return 0- Q# ]2 N) N, z# m% \# X
        elif n == 1:
    % z+ k0 b  ?* ^3 ~7 Y8 F' \        return 1+ A3 u1 `! }- r9 K
        # Recursive case8 P# ?$ L9 W# J( _$ D: ^- ]
        else:
    0 D; s8 _7 b/ R0 L4 X3 S2 U        return fibonacci(n - 1) + fibonacci(n - 2)* v* w! q; M, n4 b

    6 @( N. A8 a9 g' W# Example usage' b  V( X' ~& W% R, u' n3 l4 P
    print(fibonacci(6))  # Output: 8
    8 a4 k, a6 s+ t( u4 n; y8 d$ ]4 v8 |6 P6 F+ n3 D
    Tail Recursion
    " A$ n4 A7 V1 D: Q
    . p8 S3 X9 E$ M, O$ ~. `Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    / n0 v4 s/ N* O% ?1 ^& i$ E9 t$ ?
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-6-28 05:30 , Processed in 0.072535 second(s), 20 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表