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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 7 K0 h! M0 H% q* J- W' p7 x: {
    3 T$ j0 l; O) D& D" P( |, f) Q. j
    解释的不错# Q8 W! T" ^; e# m6 A6 s4 ]  ]

    " X5 H, p+ A( q8 D# G4 k! \递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    " f3 d/ p" {" [, k/ J1 L2 P
    9 |/ K" a8 o# ~% M: |0 K 关键要素
    ) `. x) X+ p# s3 S! e0 H" c  V8 @1. **基线条件(Base Case)**
    6 n) d0 c! \3 x5 j, w   - 递归终止的条件,防止无限循环
    4 e4 k' I7 q  j: \9 ]! G. K4 l# j3 R   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    2 W+ C: a# o2 R* j0 t6 V, y
    : E9 Y2 f3 g: Z& g5 {2. **递归条件(Recursive Case)*** k! N9 x- ^6 Y
       - 将原问题分解为更小的子问题7 g( N& h1 u  E' {4 E
       - 例如:n! = n × (n-1)!4 Z0 w. u. Z0 K& `- }- c
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    经典示例:计算阶乘# B* |9 l) x# Z3 o
    python; V% y# z. ^" Q" D
    def factorial(n):6 a, r9 m  T% m, @' P
        if n == 0:        # 基线条件
    - e2 Z4 G; B& D9 f0 ~) O        return 15 ]8 o1 B7 L" E7 s( L- p# C
        else:             # 递归条件$ L5 c& u9 K5 f; a( I0 C2 j
            return n * factorial(n-1)) ]0 s) a6 n1 W2 @9 R7 Z
    执行过程(以计算 3! 为例):
    . s$ y# m4 Z/ c! e" o% a+ Hfactorial(3)$ z/ K0 m1 s! B' E; f+ d
    3 * factorial(2)
    2 a  N! H& l0 }, C. O: G" O% f+ q. V7 U3 * (2 * factorial(1))
    * B. b! J1 D8 d4 `5 Q- z3 * (2 * (1 * factorial(0)))
    & Q7 X' h% [0 P) n+ c3 * (2 * (1 * 1)) = 6
    & R1 i- ?$ |) L1 {- X# [; `: a
    - q3 F; b9 j+ C  Y: n' @ 递归思维要点) b" X; ]1 t" q$ b* o- `! G# {0 M
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑- c/ F& l( \& d2 y" V9 P
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)1 f8 F: q4 Q+ R. `' b
    3. **递推过程**:不断向下分解问题(递)
    3 }* t5 ^& s/ K4. **回溯过程**:组合子问题结果返回(归)
    ; @% k, e0 Z' o6 q% p# z( ~+ m' x3 `6 ?% X" V% A" l. M* m% n" m
    注意事项2 b$ K+ {1 ]2 q, `
    必须要有终止条件
    % p. u. `* t! \9 H递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    5 ^, w! i* R5 J9 O% R某些问题用递归更直观(如树遍历),但效率可能不如迭代/ C) z+ O2 r- [% h1 _8 x# i
    尾递归优化可以提升效率(但Python不支持)$ {. b  f) Z. Q' O. O1 X

    " C, ]  c6 m7 ~8 P 递归 vs 迭代3 T$ |- _+ V5 S; H' l7 o* P
    |          | 递归                          | 迭代               |2 [2 `" c( }9 Z+ }5 ?; Z0 E  B7 H( [
    |----------|-----------------------------|------------------|6 _( Z# {3 v- l+ p
    | 实现方式    | 函数自调用                        | 循环结构            |
    3 e" T% |6 v0 d5 v| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |$ Z  ~2 D9 _  w! S
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |' W* ~4 `: F6 T4 E# R5 D5 Z$ U; K
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    / J. u; e1 l" ?) |: E
    " g$ B! I/ r3 R8 q 经典递归应用场景
    4 \7 Q+ _$ Y5 p" t7 Y, B1. 文件系统遍历(目录树结构)
    : D% \8 m6 L9 @6 N* S0 r2. 快速排序/归并排序算法
    . m5 {  o. g: t/ I5 W8 t. ~. A% `" Z! _% `3. 汉诺塔问题5 G& j/ W, t3 O5 M
    4. 二叉树遍历(前序/中序/后序)3 S6 {$ l$ _, g. `5 e
    5. 生成所有可能的组合(回溯算法); M; x  j* ]  ~. d3 L
    3 S& k% p- s* X5 j
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    4 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    3 n' y6 L# w  h# Y7 G我推理机的核心算法应该是二叉树遍历的变种。: A2 u! U4 Z8 n
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:6 x0 Y7 ~' f! ^  ^. P2 P+ h, k, G
    Key Idea of Recursion
    ( M4 @1 a3 ~. B+ d8 o! T$ e" i6 r- s% S6 j
    A recursive function solves a problem by:
    , J' S# |+ n8 l8 T: A9 b8 R7 B) U6 a2 l% [0 l/ x( {5 M
        Breaking the problem into smaller instances of the same problem.
    3 ^* y9 [/ K+ U0 c' j' N! m
    & W& k/ w2 U; _& {    Solving the smallest instance directly (base case).
    1 [1 Q* ]- Z& }) F, D( u
    % `) D5 i, Z8 A- v- x; \! b    Combining the results of smaller instances to solve the larger problem.1 }. _4 w: n; M. D  o0 u3 d' H

    : @3 X3 q( `* }' u0 j0 X. iComponents of a Recursive Function
    8 Y9 ^1 ^) H+ W( Q) V' Y
    / N  k" @/ f( u    Base Case:
    1 p, S! u' T: o$ Z
    8 t# L2 e  N, {9 O, m; H& D        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    9 Y8 ?% @- v. Y. o' F7 m8 J) e6 ]* o( p0 q& q! v
            It acts as the stopping condition to prevent infinite recursion." P; e& Q' D. F$ a. R: T, {
    , w& o# `1 U& V$ V' a
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    0 Q) ^- [0 J$ q, ^% E7 W, h1 O' ?* F* }6 q# k- a3 Y
        Recursive Case:% ?3 Y1 I! F8 s( s: `! _! `
    ! ?5 G% L& M; L5 r4 s
            This is where the function calls itself with a smaller or simpler version of the problem.% e8 x+ c: Z1 M3 v" P

    % @2 y& K& S5 }) z/ k+ _        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    6 F6 V4 N/ ?+ m9 ?* w% Y+ L4 g) P! A& q1 g
    Example: Factorial Calculation
    7 B) S5 U# Z, A# H+ U0 R: C: Z& G8 h7 g) [, ?2 F
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    9 H: Y1 j8 Z2 H; x
    & l2 A: l+ G8 q2 F: @; ^& J; t    Base case: 0! = 1
    1 C% q2 _4 a0 @1 Y
    ' h* c* Q1 v/ P1 V- M2 Q    Recursive case: n! = n * (n-1)!
    ! S: l( @% K  w4 s1 t5 s# C  V! Z8 s7 H$ H
    Here’s how it looks in code (Python):0 w/ Y' w' P* _0 C6 a
    python
    : I: ^% t1 _% a5 [, ~' I& {
    - i" r+ y+ Y& n+ u* a# j: u
    : ^$ u. @; k2 h2 G. s* p! |def factorial(n):+ q  e. ~# I0 h/ v# h9 Z
        # Base case
    " t, ?6 X) G6 P/ [    if n == 0:$ R0 {" x' j, G9 T, w& ?0 C
            return 1
    ( G2 k( i. S; F& x% v! p% y    # Recursive case
    9 y" z+ G: [" ~: r1 N& e% J    else:1 R8 `; ~4 G/ r4 C$ B& {
            return n * factorial(n - 1)
    2 \1 S2 V+ B+ C0 s
    / z. s9 Y% H7 b3 `8 f* k# Example usage
    ' N- U* K/ z# {! j) S5 lprint(factorial(5))  # Output: 120
    : H( D9 I. T/ }) s
    & L! u; ?  g+ P! x+ Q6 IHow Recursion Works" F! ?; o& a( ~8 r! c9 L4 S1 h
      p6 K0 U, C  M1 f5 h5 Z2 |) f
        The function keeps calling itself with smaller inputs until it reaches the base case.
    3 K0 P+ r; [6 [( Y; S
    7 Y( A& I3 Z9 l    Once the base case is reached, the function starts returning values back up the call stack.5 R3 P' e, q0 x7 J+ G+ V# H
    1 i$ }+ P" u0 e% ^* [
        These returned values are combined to produce the final result.( d& _& E' p, ]& b. D  s$ p

    ! T5 {3 S& P4 b& d" t% K& oFor factorial(5):
    * w/ Z0 t5 \+ L! @# x. o
    - m" v5 d# n) ?3 L$ |( N# |% P! ~/ n9 k
    factorial(5) = 5 * factorial(4)
    " p4 n5 b7 C  Ffactorial(4) = 4 * factorial(3)
    $ U" \4 D: [1 Y' Bfactorial(3) = 3 * factorial(2)4 I; b1 ~. w8 R# ?: a% m
    factorial(2) = 2 * factorial(1)
    4 r/ F/ Q& m" \4 R: Kfactorial(1) = 1 * factorial(0)
    8 Z) t* g# P% t& W4 m8 h2 Pfactorial(0) = 1  # Base case
    1 y% h$ K& U+ _
      X8 X! z4 t# ~9 }Then, the results are combined:
    & V" I9 k: e) ?, ?+ G1 l; A
    3 O: v) r) D4 C6 r; X" @  ?! o& V9 {
    factorial(1) = 1 * 1 = 1
    6 F$ @1 c% l& M6 c# M3 pfactorial(2) = 2 * 1 = 2
    3 {: a9 ~- h: a1 \& ?factorial(3) = 3 * 2 = 6- J1 c" @& Y! ^$ i( J( A! \) l. x
    factorial(4) = 4 * 6 = 24/ `' S/ C; J0 z, t! O8 H/ O  a
    factorial(5) = 5 * 24 = 1204 x' J, g) G! e5 y! t4 }

    8 T2 c! B( L2 @" ~. HAdvantages of Recursion. O$ M, @9 K% U  i
    ) M  I. q- q/ }$ I. V
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    , V  X0 K8 E3 ^  L+ X
    ; [4 B/ _2 c( q' @/ [( z    Readability: Recursive code can be more readable and concise compared to iterative solutions., V! ]( h: K+ h8 I; t, |
    $ N2 ^6 ]; R% E# b8 j1 f
    Disadvantages of Recursion. F9 N/ n4 w0 g0 O$ |

    3 A: |: S( {: H3 _    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.& v4 Q8 M9 z& b, ]* z- D

    / R7 r* _' g6 B7 Z8 Q. m9 H$ Z    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    5 z! ^2 n& _  h, R9 G" ^0 z1 A5 }4 a. H) v  R5 X( L
    When to Use Recursion3 c! y) r  J2 ^4 l/ a

    8 G9 J3 a: |: o2 A) ]& |- R  [    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    0 V/ U4 u  j) n9 q2 B" _
    6 }5 k9 Z' z$ j    Problems with a clear base case and recursive case.
    % c1 f- M3 _- H0 w$ E! ]: e0 w! {; e8 x- H% N# c  U
    Example: Fibonacci Sequence- D# o( _" m' H6 |) |

    4 S* M; |: I& Y# a: [) A- P; u. jThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:" B2 G* b4 {) H0 v, O
    ; U$ s, W3 M6 R- B2 K8 |
        Base case: fib(0) = 0, fib(1) = 1) i) J; o6 \9 n0 \  X8 \7 \
    " _3 ?9 |. `( N( ]  w9 T! S* d. ?" r0 ^' Y
        Recursive case: fib(n) = fib(n-1) + fib(n-2)$ k4 w" x  }0 j7 o

    9 L1 o# J/ Y. i+ vpython
    / _4 ?5 X3 k. Q* o: \5 E9 `( h. d; h5 q5 `0 l% f) S! f
    + I+ g( X& D7 j) ~! [$ `; C
    def fibonacci(n):
    7 ^+ c8 D  y6 }; j3 p% U    # Base cases
    ! e1 P0 ~3 F3 \1 \3 j' _0 P& ~: f* k    if n == 0:
    8 G6 E9 V3 T1 p        return 0
    - P& G) ^; Y  Z! P    elif n == 1:
    ! ]9 c2 x7 }" v. [        return 1
    7 U" q/ y+ L3 r& L4 n    # Recursive case$ A. [' w  Y" x: U- X9 F
        else:% N3 ~1 \* n7 Z7 B9 u
            return fibonacci(n - 1) + fibonacci(n - 2)  O4 k0 P: C2 v. j4 p
    % v. h/ q9 s( q. _' ]
    # Example usage
    / ^3 ?7 J% ?% |0 pprint(fibonacci(6))  # Output: 85 E0 o6 u; d) }  x' S7 E

    ; o( R) Z. A, J! A7 CTail Recursion
    # ^# b8 _; k' G- N; }3 ~) W
    ' {- x( f- A. e7 K% M/ JTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).* o: D5 F2 c: ^
    ' r4 o& f" p' O8 v4 b- J
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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