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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
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    9 j) r& W4 _' ]% K/ k解释的不错/ K/ @( S9 b' |! R. y' X

    1 P3 X3 ^6 O/ M7 L9 E6 k- i9 f递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。) j: d6 h3 g& q- k* a0 u
    4 F" Q" \) _1 j% T7 r, W. r+ ]
    关键要素0 a2 m1 N1 ^& k2 E
    1. **基线条件(Base Case)**
    . E$ h4 `. u% z, z' c! v   - 递归终止的条件,防止无限循环  C/ }; }7 u$ @5 n1 t1 h# s
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1" x9 a% N% ?0 K
    2 F/ p- a" i2 f- ^8 ]% R
    2. **递归条件(Recursive Case)**
    * c( A$ S/ {7 E  n% \# \   - 将原问题分解为更小的子问题
    % v. \  y6 ?: o. h# `) N( o   - 例如:n! = n × (n-1)!7 p# \5 Y4 [! v* L" T

    2 z: o* J- C) O- ^& Q+ r 经典示例:计算阶乘
    ! n' b0 O2 M; X. X/ ppython3 e" k* O, Y: B2 H: ]0 t" F4 T
    def factorial(n):
    " v; U7 q( D- ], i2 }: O$ a    if n == 0:        # 基线条件
    4 U& v0 G6 }) C5 V  _7 J- ^        return 1& U4 i4 ]) c5 `6 F* J# F
        else:             # 递归条件
    * L% \& I# y' ^" _' H% z/ j( h% A        return n * factorial(n-1): l& [1 F/ ~/ ]
    执行过程(以计算 3! 为例):
    / M9 z& H4 a) s: A7 w# ?) efactorial(3)" r0 z  z' W# ?" B+ ]0 A% c
    3 * factorial(2)) D% v" Y2 t2 d
    3 * (2 * factorial(1))) [! s4 _- _* e8 ~* p/ Q
    3 * (2 * (1 * factorial(0)))4 Z8 v' K' R; @2 C1 J1 v1 A
    3 * (2 * (1 * 1)) = 66 A$ O6 d' M" `) f6 H3 |  w
    6 _7 B0 p- Z- U6 y
    递归思维要点$ H7 U' o3 _; j8 _2 N! u  Q
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    7 x' ~9 J' X* o5 A0 U) Z2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ( i" k+ E5 R+ \/ I! {+ b) g% V3. **递推过程**:不断向下分解问题(递), d& t  a5 A( S" I. ^6 a
    4. **回溯过程**:组合子问题结果返回(归)
    ( g1 R9 v: |! ]( {# Y9 h4 W/ U& l; ?; j
    注意事项
    " L* n7 V  o, m7 n9 r: l必须要有终止条件; g* c4 j1 u7 I) A& B
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    $ {- {# a% ]) k3 U% H! h) O. {某些问题用递归更直观(如树遍历),但效率可能不如迭代
    # v4 n4 [+ r7 I0 S5 m; z* ]4 ^尾递归优化可以提升效率(但Python不支持)
    2 z/ R, ]" j) n7 n2 J6 f( @
    $ m; g+ B9 i+ D5 W, O) S( T# \$ B3 u) r 递归 vs 迭代7 Y5 B4 b7 W+ Q" {1 U
    |          | 递归                          | 迭代               |
    4 S8 `: O( u5 u2 ]|----------|-----------------------------|------------------|
    # h; I9 b9 x" ^6 W3 N| 实现方式    | 函数自调用                        | 循环结构            |3 f2 u7 B* M9 T
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |5 e3 f& O" V+ }6 H
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    : a6 \: p; d4 ?8 n6 B| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    " q/ Q+ Y* \, O9 t  w4 }2 J; {+ o. Q& t* z0 V
    经典递归应用场景- L4 k, k/ }- u
    1. 文件系统遍历(目录树结构)
    2 U# J1 y1 O1 ?; E) a3 t. T2. 快速排序/归并排序算法
    ' j0 x) m; Y9 K5 K; x% Z3. 汉诺塔问题# T* g* F* F$ u: j6 z' p
    4. 二叉树遍历(前序/中序/后序)3 A. _4 c8 M! g, {
    5. 生成所有可能的组合(回溯算法)
    5 L1 i. K0 t1 o1 W' |; m
    5 p; }6 d0 f3 ~' Z试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
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    昨天 06:38
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    * S9 Z7 k1 z8 z% L' x9 }我推理机的核心算法应该是二叉树遍历的变种。
    * E1 ?% F6 G0 h7 e% @另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:+ b; G+ ^* M% v3 Q
    Key Idea of Recursion
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    : ]4 N! f' z2 n# c. CA recursive function solves a problem by:
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    % o: G. y2 k& \    Breaking the problem into smaller instances of the same problem.3 n% U" E" i- ^& R, o1 x
    ( d5 m" ?4 a6 h3 a
        Solving the smallest instance directly (base case).! j: |' J2 W) {; {- z
    6 A2 d7 L0 w% y$ @: [9 @
        Combining the results of smaller instances to solve the larger problem.
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    * x* T% N/ L. h+ Q9 aComponents of a Recursive Function& f/ ]* ~- D5 @$ Q# `4 z4 }
    1 T' m- X0 q: x$ W& F$ _
        Base Case:; d# }2 y- a/ n8 d! s
    # c; @; U# w! `" _$ q
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    8 U5 |. s% z" Q8 f/ _. U, j" D6 x# L* ?6 `7 K* t
            It acts as the stopping condition to prevent infinite recursion.2 w. E3 k2 E& {/ }1 y) a
    $ J+ P$ f2 E9 X: `" B
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    & g4 J2 t% D+ L2 o: \$ x5 ^8 p9 }
        Recursive Case:
    . B+ B" P% S; x3 G1 ?% L# Q) |* `, h' ^, C
            This is where the function calls itself with a smaller or simpler version of the problem.
    + v7 M/ v9 G; I( W' Y6 X' `
    + M9 E, v6 }# p3 K        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    8 u3 G7 @9 S4 M% S& b  b8 L. ~
    ( V; R# X7 }" k* F" P$ q& _Example: Factorial Calculation+ R$ Y: [/ H2 R. Q6 E

    7 |8 a) y" z1 H9 Q5 kThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    + ~4 F! A* }' p  q& U+ b  p+ T) b1 A
        Base case: 0! = 12 M7 Z$ Y6 \: A& A) ^
    / D1 J  |9 |* `
        Recursive case: n! = n * (n-1)!
    8 i' |7 [5 t; D# k$ H* D& s( L1 K
    # ^* f5 y* w: ^. o' C; NHere’s how it looks in code (Python):
    3 w  A. B" G2 ?& Y5 Z4 Vpython, k6 f! I2 p7 S. a( T
    . ?& G' J! O- ^% P  k: M
    7 S0 w, o: Z. ^  O
    def factorial(n):
    7 ?( q9 I$ ?+ @' m    # Base case
    1 [/ ~2 s& R4 b( O0 W    if n == 0:
    6 B; q  O* v% F+ w- t' d" y        return 11 k# V) D% ]5 r) s8 w3 s& @
        # Recursive case
    2 j1 Q+ M, z! {* }* h! B    else:: y( o. t+ x) J6 N( z
            return n * factorial(n - 1)) x4 }& t/ a1 x% F2 z  X" f
    : f5 s1 Y, f2 W. D- U
    # Example usage2 |7 [) c' _) W
    print(factorial(5))  # Output: 120
    ! a6 |; p2 X, Z& B( T
      O- N2 T3 m. nHow Recursion Works
      L# O  i6 t3 ]" D$ Y0 S+ J  w1 v6 @  S
        The function keeps calling itself with smaller inputs until it reaches the base case.
    6 l3 l% x5 g6 s' Z: [/ P0 d+ `- o9 i! V+ h* z3 G  Z6 j
        Once the base case is reached, the function starts returning values back up the call stack.
    ) M$ S  ?7 L' _4 f& D
    9 L+ C' R" m* x/ W    These returned values are combined to produce the final result.7 k" W9 i! b" x4 G, i7 I& G
    # L! ^, y2 O0 ?+ c
    For factorial(5):
    $ R; b4 n7 P" ?, M' U& K, d8 Z6 X. M3 F% {9 W; D1 ~  N3 l4 K
    8 j7 T$ X- ^# r- E
    factorial(5) = 5 * factorial(4)
    5 u. B1 ]9 G1 _factorial(4) = 4 * factorial(3)/ `4 e- H( G0 Q+ p5 Y
    factorial(3) = 3 * factorial(2)
    " l& u2 ~4 Z# Z" x9 K" d. pfactorial(2) = 2 * factorial(1)( q. e7 D6 R" c& _
    factorial(1) = 1 * factorial(0)5 x* l& p7 Z9 ~3 |3 i6 f+ h
    factorial(0) = 1  # Base case( `. @7 F' I, y& b2 v; o

    ' z2 L* C5 T+ C" U) YThen, the results are combined:( e  ]4 s# B  C6 o1 l0 S& k

    ' X0 ]  y, \* i3 }# f
    5 r2 R. O/ `, i. K- afactorial(1) = 1 * 1 = 10 o% G8 S8 [1 n  C) X3 ~  Z
    factorial(2) = 2 * 1 = 23 U+ z9 o8 P6 e2 F6 J8 X
    factorial(3) = 3 * 2 = 6
    & i7 l* n9 s  e1 f9 ^factorial(4) = 4 * 6 = 24" [8 p# t2 f; a1 ?, q( v. P
    factorial(5) = 5 * 24 = 120, k  b! W) N/ k: G; g9 l- J
    : H( ]- F+ g  h; c
    Advantages of Recursion3 b( v, B: a4 I
    ! @4 x& e( e/ m# d1 M
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    & H, {0 u. t5 f" R+ M+ @) R1 A" E4 J" A* d, t- ?
        Readability: Recursive code can be more readable and concise compared to iterative solutions.' |$ R2 R, t' ]3 B2 ]. e
    , V+ K9 B7 C# i
    Disadvantages of Recursion
    9 r8 B& H( E$ V( b3 w8 N. W4 M* u4 J# a
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.# W# E* S  q( w" \
    , L1 f" X8 l6 T. B. h4 U8 _) z% a0 Y
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    * V) J* O7 Y- l( Q, Q9 Z* W
    ; a+ Z7 @+ ?7 g0 \# MWhen to Use Recursion
    " j( t, S% N2 ~: u6 l
    . ~* ]7 |7 w* n7 F9 V! R    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    3 o" S$ _8 _$ K( u1 s  ~
    $ w$ k/ g% ^7 w    Problems with a clear base case and recursive case.* I9 W6 \5 n  ?/ J
    ; ~+ R0 H) i  M
    Example: Fibonacci Sequence
    . j: i1 ]1 K) s( m- r5 n+ _
    % ]3 V, j8 S" A: t! J+ X: u" Y- GThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:1 ?, h+ d4 a9 O0 B9 p4 ^: c/ u3 @
    1 G& C/ N# c- b' g  s2 g' E
        Base case: fib(0) = 0, fib(1) = 1
    7 P% ?, u! j" R8 _) p% t& [2 U- I5 O+ t7 U3 F& s% s, ]8 P+ F2 U  l
        Recursive case: fib(n) = fib(n-1) + fib(n-2)9 P: j  _% d, j6 u* ]' }
    4 m+ O7 U% V/ j! ^" C
    python
    1 J5 l- {) ]' X$ q3 F9 E, O6 }- e/ P9 P( M1 C1 j* g

    ' Q! x& _. s: Cdef fibonacci(n):
    5 I; u0 }: ]/ i  ~5 _    # Base cases: W+ o/ k2 r4 f
        if n == 0:; Z  Q7 C  h. Q  g6 S
            return 0+ b" j, s, b( J9 K7 t0 v
        elif n == 1:2 `, j3 `- q) b
            return 12 o# \: I! o! V3 L$ p5 g$ F1 b1 R
        # Recursive case; u# P2 a8 H  V3 h. ?/ Y( Q
        else:) |* c" F' P" ^, g
            return fibonacci(n - 1) + fibonacci(n - 2)
    . Y/ {2 {, d0 t/ J. r" Q0 a  S- S( f
    # Example usage
    0 M9 a  N9 Z' c' k7 m  k: vprint(fibonacci(6))  # Output: 83 ?$ E. @6 K& x4 i7 C

    4 R5 d& l6 W6 o8 R. X$ @( RTail Recursion
    2 R& ]1 k. x" z  D3 X
    9 N: C) ]* m/ x' cTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ! |# g; r6 a, n: y5 F, p# v8 k* c% @1 N$ b: l8 P
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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