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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    * S4 S- }2 T; s7 Y$ h" C$ ^0 x4 I+ q1 U) ]% B& {8 R! Z
    解释的不错' v8 J& q% k3 ^" q3 h

    : i7 s! i1 F3 k) r; `, T, G递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。7 u+ W& y, D# E( f: K' u

    4 `) r1 J+ }& |& O 关键要素- D) Y6 p7 a( S
    1. **基线条件(Base Case)**
    1 U) Q9 I+ Z2 [- ]   - 递归终止的条件,防止无限循环2 I% t( c" U, F4 j. {
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    # v0 Y  z" Z) O8 K) B1 L; C% f2 c9 s+ E' b( s( R1 A- J0 W% J
    2. **递归条件(Recursive Case)**
    ! o$ ?0 ^& _9 r6 e4 U   - 将原问题分解为更小的子问题
    9 W6 f3 g- f% k2 m   - 例如:n! = n × (n-1)!
      U2 w9 a& u: r+ ^5 n1 b, K: ?8 y4 u1 R1 w- o
    经典示例:计算阶乘
    1 I0 S: c; u& `9 ppython
    + f& S' s7 S2 a1 [  [4 _. odef factorial(n):/ _; [2 g& K( n, _
        if n == 0:        # 基线条件
    + E3 A  Q* X5 J- J* s        return 1
    7 E" z& @5 f$ i1 ~. Q. W    else:             # 递归条件2 w5 @# k3 B" J6 v- L2 b5 P
            return n * factorial(n-1)" Z4 V* q- r" Z- {9 _  P
    执行过程(以计算 3! 为例):1 y. s- G' J5 I5 u8 y7 ?6 a
    factorial(3)4 _# ?' m: l4 b
    3 * factorial(2)
    * o+ ?2 J; w2 q  \0 X3 * (2 * factorial(1))1 K. c& P9 |! W- d3 _0 I
    3 * (2 * (1 * factorial(0)))% a. w9 V" Y8 S# e- k3 L- x; n
    3 * (2 * (1 * 1)) = 6% p# y9 j8 y" @+ N$ v, r' D
    1 f3 U. B0 J0 j- h& B% ~
    递归思维要点
    2 t0 C- P! T, d" ]: |1 ?* y9 ?1. **信任递归**:假设子问题已经解决,专注当前层逻辑! W3 _$ f* L! T* Y7 f- ~; C
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    / A: D1 l6 I! N3. **递推过程**:不断向下分解问题(递)
    : K/ s4 p7 n  U, n# C, |* L4 Q4. **回溯过程**:组合子问题结果返回(归)6 N- {6 T7 r4 Y  C7 K9 m/ M. ^

    % l% I( }; k: N+ h- N! w4 p 注意事项
    # Y+ c: Z  f! Z( ^# n! G+ _必须要有终止条件; B' c6 Z3 M! R: M  k
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层): ?$ C5 {/ b8 M5 j  O
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    % Q5 }, Z4 l  B& o. c* `尾递归优化可以提升效率(但Python不支持)  ]) J6 r7 a4 S9 m
    9 n3 ^$ h# }' Q6 z4 o8 U. E) s7 e
    递归 vs 迭代
    ! b0 A( H2 G/ f5 k  w1 D|          | 递归                          | 迭代               |
    0 H+ a( E( z5 b- W|----------|-----------------------------|------------------|
    # s( ]8 n4 i- ]5 w| 实现方式    | 函数自调用                        | 循环结构            |
    5 A3 \: `/ P' f4 S8 _6 m% B2 _| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    6 s9 \0 q0 T7 d# F- E* E( k| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |* S! E, j4 h, a" H
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    & [: H0 \: r" w. R9 M/ ?/ i1 D) M5 v) j; @9 t5 ^( r1 J
    经典递归应用场景% e) J* y1 ~, K8 {2 W$ d6 v
    1. 文件系统遍历(目录树结构)
    ( M0 r; {# h9 J( [2 r0 B( k; S/ ~2. 快速排序/归并排序算法
    * D) s" {% s. v$ Q- N  `) a; M3. 汉诺塔问题
    2 q/ F1 f1 y6 M4. 二叉树遍历(前序/中序/后序); _* [" k3 T1 J% h+ s) u
    5. 生成所有可能的组合(回溯算法)
    ' i7 D  d+ P" d, r0 ^- Z, }) l) G- f0 C: }
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
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    昨天 05:46
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    ) |8 @/ z+ o7 t: ?4 u我推理机的核心算法应该是二叉树遍历的变种。; S) ^/ K3 F' }
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    * w+ e  |" ^5 b' n# H& EKey Idea of Recursion) w8 F4 l- r) y, Y+ M) ?

      g  h" e* c! wA recursive function solves a problem by:
    & [9 H, W) q. d5 _( n8 R, B
    9 n4 y+ }" A! S0 O9 i$ }    Breaking the problem into smaller instances of the same problem.# q/ s4 p; w, e5 B: A4 \, ?; ]
    $ r+ F+ g3 u* R& a! c& w! ^1 \
        Solving the smallest instance directly (base case).6 Y0 J/ b; A# \8 Q7 o
    ) e* D1 J/ t7 D" ~& U( y
        Combining the results of smaller instances to solve the larger problem.
    8 f0 T+ S& |2 [0 F: k3 W! |
    " u/ v6 h/ W& w" M0 {5 \3 {Components of a Recursive Function
    9 K% O, d6 N1 s2 L6 E
    $ J" c* X2 a- Y8 h0 D" w( W    Base Case:
    ( \1 q, g" l$ o4 x, d, u! D) e! B, u" }4 J. @( s0 r4 f
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    ' `2 }% ~. {+ |7 p$ ]+ k( C" X9 Z2 u1 h/ o9 q7 u
            It acts as the stopping condition to prevent infinite recursion.
    : X" H3 ]) n0 i" y3 s8 Q) ]$ b& S9 \8 e) X" ^- F
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
      K2 g( B* P4 P9 Q' g( y1 n
    ) a5 y( j. o0 Y) c3 C    Recursive Case:. y* ~, W: T( |( p/ _5 ~& m; t: x
    6 i4 b: U, k$ v! z4 ?
            This is where the function calls itself with a smaller or simpler version of the problem.% ^. k; o* s8 K( R. n6 B
    0 Q, F+ U3 q5 g) _8 ]/ v( i
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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    # {2 b8 q! J/ K3 B* P6 |, `Example: Factorial Calculation2 m* u( Y. e* b3 u. o* Z  y9 b4 D
      M9 N# j: S* l5 Z( r; h8 l  A5 b
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    4 |* D0 L; O1 C! X# X' G" T/ D& q- O- g% [" R+ ~1 o8 Y
        Base case: 0! = 1, m5 B3 Y0 A8 Y
    ; O$ d6 a' B. n  I+ f% Y
        Recursive case: n! = n * (n-1)!, @% X, A( Q! N% c8 w5 T

    0 k6 x2 G4 y! V3 t5 h5 AHere’s how it looks in code (Python):
    + q2 d5 U, K5 B. F+ o7 [python7 }4 v5 V3 P  ]; S2 S

    9 Q# [/ M1 o0 n2 m4 k5 z* o6 b3 o  T1 i# V9 m5 X. J
    def factorial(n):
    0 \$ N' h) _. f% I" ]    # Base case
    1 }, Q* G7 l1 `) f    if n == 0:
    * G0 \1 U* G1 g8 h8 l        return 1; g0 j, o! ^* {5 N3 \  |" Q
        # Recursive case+ x: d3 O* i( r2 O- c1 Q
        else:( \7 T+ ]/ ]3 ^# G- C3 ?7 J: j
            return n * factorial(n - 1)3 Y# Q7 s3 B# b5 b! S
    8 C4 g2 N. W) b, s. u
    # Example usage
    . G1 h- y) P: v) G4 @1 x- y  k7 {print(factorial(5))  # Output: 120
    - _8 I- C; _. |' S: i1 F) h5 k9 |
    1 B* |% R3 E3 w! LHow Recursion Works
    $ z5 q+ n: _, L( M% E# s
    - X3 k( _2 I( D1 |( r/ f) o& X    The function keeps calling itself with smaller inputs until it reaches the base case.
    ! s4 Z8 S$ w' ^* t& A4 J2 S  `) y& Q  ]$ e4 J, ?
        Once the base case is reached, the function starts returning values back up the call stack.
    9 Z% K! `0 m4 K  W+ i9 c/ S# e+ z+ o$ O: f
        These returned values are combined to produce the final result.: g( J8 k6 U2 j7 Q. M/ M0 P$ T
    1 V; J% _2 ?; N; @9 \
    For factorial(5):  ]! i* |* J7 N0 x3 D/ F) W

    & w% B- p# l/ q& d  x0 C" e" @# p" K$ C: K- P$ b
    factorial(5) = 5 * factorial(4)
    ! K: p. |, U& Z9 J1 `, {2 M/ wfactorial(4) = 4 * factorial(3)
    - p! _9 _" R: ofactorial(3) = 3 * factorial(2), C6 f( X; G8 U( S) A$ U. L
    factorial(2) = 2 * factorial(1)5 R3 C) F3 p6 q7 S" b
    factorial(1) = 1 * factorial(0)( z4 N4 S! X9 Z0 q7 Q) B
    factorial(0) = 1  # Base case# N2 ]+ A! u& ]8 t, l! B
    ; K8 a8 y0 w* [; |. q# R6 a# Z8 s* h
    Then, the results are combined:6 `& z& Y/ @3 `4 L8 R# R
    7 C1 Y3 J( X- `- E: a" x" M; @+ I
    9 l7 W2 Z! ]2 j; b% k3 t+ h1 U3 t
    factorial(1) = 1 * 1 = 14 l+ H4 C/ y( N3 }; v, e' F/ R
    factorial(2) = 2 * 1 = 2  J$ S1 [1 U+ y
    factorial(3) = 3 * 2 = 6, h- g8 e$ K3 M* u
    factorial(4) = 4 * 6 = 243 Q8 J5 P3 Y% {
    factorial(5) = 5 * 24 = 120
    2 G* i, ^$ z) \2 j9 _( S
    ( \  N7 }% n: Z0 R* y% BAdvantages of Recursion
    % T3 ~  o1 M. b6 C- B
    0 p  k: s; B9 q, Z    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).0 k3 D+ h) }  x* H) P* B! y6 G  z
    0 K# F. A( q" ?# P
        Readability: Recursive code can be more readable and concise compared to iterative solutions.  r( ?- i2 X2 {. a
    8 @; k6 h# ?! N" @
    Disadvantages of Recursion
    " u) I! P) ~6 ]5 y3 I1 v) M
    0 p2 ]* w8 I6 h0 c    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.* s3 k2 G& g% \) y  }. R$ I+ A

    9 E( w# O8 y, d* T9 z" J" b    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    ( Y9 S, U4 ~3 M7 M1 z
    $ t/ c  z" X! N, Y& RWhen to Use Recursion0 ^6 ^; ^/ J* U
    + }) S( O8 s( S0 O2 f
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    ; ~3 Y' K+ Z+ U; p: P6 v) ^* t  O5 h. {
        Problems with a clear base case and recursive case.
    * o! d/ O3 k9 ?+ f, k# Z1 Z, L$ e0 R6 @
    Example: Fibonacci Sequence/ T' A: k+ B* [: Q0 T
    2 z1 W1 [% W) p9 u- e2 z" N
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    3 I0 ^: s) k9 g4 t
    ; N# U# }. G( Y* [    Base case: fib(0) = 0, fib(1) = 1# E. h+ f0 u3 x$ F
    ' s  d0 |- S& S( s# s+ a- F9 ~
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    7 y9 E% h2 k' [) _: e1 g  }( v. Y5 k( B' Z" }
    python
    4 H! x4 ^/ }+ o) R; R! w2 E
    6 }' x& t8 G: @# n2 v+ ^5 t
      Y* N8 f( Z. p1 _* C2 Tdef fibonacci(n):) P2 \9 O( b& K2 P6 N' i
        # Base cases
    " K6 x! x$ Q: ^& v" Q. p    if n == 0:
    , W3 }, |% ]$ h0 Y2 b+ T        return 03 G2 ?: e; x" N% C0 ?- \
        elif n == 1:
    $ W+ f6 T6 }/ J( |  f        return 10 u5 k; R0 a6 r7 `0 {
        # Recursive case' H9 [/ ~! W/ v/ Y
        else:
    $ D) N, O# a! Q! U6 M. F5 g        return fibonacci(n - 1) + fibonacci(n - 2)
    ) e; {. s/ [+ m- p, R* e2 k8 B
    + _- H6 y# A: x# O! c# Example usage
    , q# l& ^( J( r- [  c+ t. E$ _print(fibonacci(6))  # Output: 89 ^) z/ U  h: F8 Y& \

    2 Z0 X3 X) G5 \. b. }" H" zTail Recursion9 Z1 }3 E0 R! w& w" {
    7 {! I" k  L/ Z( g! s: L
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).( t" [5 P& p3 q! e5 E" v

    4 e" g9 h/ @9 G% w  j: s. k1 L: EIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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