设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2929|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    8 C% L& D) T* L( @( h8 e% M
    ) X7 J. n# v* E0 W- C" y" z! _& D解释的不错
    " v6 n. h) J: U3 g& ^
    ( G( R8 r/ U! G6 w递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    - N" H. D, g# w5 i6 G
    + f, ]4 G4 O" r" Z5 T5 v; H5 u* o 关键要素, J( i- A0 R1 n
    1. **基线条件(Base Case)**
    # @9 ?; {9 C, I$ @. o3 P4 o! a   - 递归终止的条件,防止无限循环
    ) g3 q) V7 Q1 \. f& Y$ P0 v   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    1 I: h9 `* N' @
    5 z0 U. r5 z/ R5 [+ F& U6 D2. **递归条件(Recursive Case)**
    2 F2 A- S0 p1 g2 E4 F   - 将原问题分解为更小的子问题0 Q: ^3 x) E: i
       - 例如:n! = n × (n-1)!
    3 N: c6 I8 P, C' ^) x& V1 b/ j* b4 w) z; H' H1 @) O& Q9 A' B
    经典示例:计算阶乘, r+ [# L$ e( b# {
    python
    1 \& H2 Y% Q- @; C" Q( Idef factorial(n):$ A) U3 |7 ~: K: |& J6 z  k% `
        if n == 0:        # 基线条件
      X- @9 n% x3 @) D0 _) t& g; x. ]        return 1' M0 h( p1 }7 y" I/ w) n  J+ P
        else:             # 递归条件
    # ?2 r6 m& c4 _7 o  X        return n * factorial(n-1)+ h' x8 ]# x. h! N: L
    执行过程(以计算 3! 为例):
    ! T; S7 l+ R1 E5 `0 tfactorial(3)' {4 F/ M; a9 T; _6 X# A
    3 * factorial(2)/ m! e: z/ A2 ?3 U- b; a6 H4 k6 W
    3 * (2 * factorial(1))! v' ?3 E  w! x8 S( h0 E
    3 * (2 * (1 * factorial(0)))% p, H" R8 H: d* P* s9 e. e
    3 * (2 * (1 * 1)) = 6
    8 P# {+ ~0 _0 d2 }8 V0 S& x. l* T0 y+ P) f  A
    递归思维要点* V, C6 e* @% t* |
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑1 x% {$ I1 |6 _* H
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)  h: |3 v3 l; o
    3. **递推过程**:不断向下分解问题(递)
    + g/ S( z) w" k2 Y6 A4. **回溯过程**:组合子问题结果返回(归); i1 a; V& p9 N* I/ n" ^
    9 C- {( W# M$ t
    注意事项
    ) X! `$ _% H& r5 J7 r& f必须要有终止条件
    / ?8 N2 Z6 P8 G递归深度过大可能导致栈溢出(Python默认递归深度约1000层)6 V$ B! O7 O6 \" Z* S7 P4 Y& p/ _
    某些问题用递归更直观(如树遍历),但效率可能不如迭代3 b) T+ u: v$ [& D. B2 m
    尾递归优化可以提升效率(但Python不支持)
    7 M4 |% _+ f2 f5 a8 k; E, n
    ' `. i: P! [/ A: D7 i0 M 递归 vs 迭代5 R. ~( j3 c2 a+ m6 k# m7 j2 z- W
    |          | 递归                          | 迭代               |5 V+ C& r, u2 h
    |----------|-----------------------------|------------------|
    $ o, M/ E/ j, {; Y2 v, p6 O| 实现方式    | 函数自调用                        | 循环结构            |% ~! b9 Q: `* C. k5 Y
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |2 f% ]  r3 V2 m* W! ?
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    % I( A2 O. ~" o, _. _; Z3 U. K| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
      A5 Z- v8 N2 B9 F: O
    $ E' J5 L' ^# }! i& e# M5 c3 M( k 经典递归应用场景
    * ^0 q6 A8 j8 a$ C1. 文件系统遍历(目录树结构)
      G# w# I8 M" \2. 快速排序/归并排序算法
    + W: Z. i) |2 f' G3. 汉诺塔问题9 t! l0 y% M; b, t+ i: Q
    4. 二叉树遍历(前序/中序/后序)
    2 d) z8 P7 H8 k! C  Q1 [" P0 p8 q5. 生成所有可能的组合(回溯算法)  H6 \7 Q- \' C# L" K
    4 e, A& S" W# C: V
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    奋斗
    昨天 08:56
  • 签到天数: 3281 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    , h' q. E1 \( \. Z8 j7 I1 ]我推理机的核心算法应该是二叉树遍历的变种。
    ; D, V8 N( e2 q, p) r另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    9 x# B  d/ A- }( W' ]/ YKey Idea of Recursion
    / B. {2 B% c- J# }4 h* A
    4 p( J2 S4 y5 J  JA recursive function solves a problem by:
    , n1 ^1 m7 G# p- ?$ ?& t* k, {
    2 q# G0 {) P$ B  M8 P    Breaking the problem into smaller instances of the same problem.
    # O9 v, z; V2 S
    : s, n2 F4 H9 h    Solving the smallest instance directly (base case).
    9 L) T6 y& S- L1 B7 C
    8 ^# {$ z- a5 X    Combining the results of smaller instances to solve the larger problem.
    5 x. p' C  R  ~7 w! t4 A5 G$ z' O
    & {  D8 f) ]) @Components of a Recursive Function5 i- b+ T' S; V" Y
    + ~; o+ G6 l! {' f; I
        Base Case:
    , x4 _; t; J$ C% q# W
    ) l& w6 w) \  g8 b' ]0 D2 f& A        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.! ?" x. S2 U# f8 E' k# N% \, Z

    - A1 r" ?9 P7 s+ D* b        It acts as the stopping condition to prevent infinite recursion.
    ) W( x; V9 t4 d( d( v0 N/ A( W0 q
    ' g! b2 T. a$ B& c* n( q        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    ( N5 u' X4 l! _1 a: ]: |) T1 h* s7 [8 u$ d: O0 x9 `9 |: ?
        Recursive Case:
    , I0 i" a; \2 i9 P  G( a3 _- ^- V4 x5 b
            This is where the function calls itself with a smaller or simpler version of the problem.
    3 l3 F/ L3 ?5 U' z4 ?- c/ b0 L; Z
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    ' R1 B* D/ ^9 _8 N! M- M
    . g7 ?# D& w  F2 R$ K& J6 GExample: Factorial Calculation
    - Y4 F* j8 w# s# M2 E( Z) B' t! H  s' s8 _; g, h
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    ' d5 d1 ^7 C+ S) @) F7 u/ i
    / _: {: M" t+ m6 v    Base case: 0! = 12 a( B2 z* b8 Z6 h# Q
    " ?5 H! ^+ p0 I( b
        Recursive case: n! = n * (n-1)!" a! I) M5 ^- r" g" w
    0 y( g' [% F# S2 C5 D
    Here’s how it looks in code (Python):
    7 d1 V( I' X7 T; o7 _python
    . D0 X' ^$ Z6 L  ^2 a+ h, B! p* ^# P, s( P* U( q3 H, k. q
    # y! n/ ~: c  [! f. F
    def factorial(n):
    - ~: C, r" J- ?+ t! d+ Z" s    # Base case  K  h/ \2 J8 ^  m
        if n == 0:
    0 }! s% `! Q  @" R" b" y# \; ~; E        return 1/ o/ |/ d0 K4 X
        # Recursive case+ G3 {6 k- h' {( k" }' `  j
        else:
    ! d) q# _1 a1 m7 G1 ]        return n * factorial(n - 1)
    2 c& }1 M, [: x9 {+ b$ \& Q& d3 V
    # Example usage
    ) f- J; ^4 W5 N2 I" U( w7 w+ vprint(factorial(5))  # Output: 120/ a9 V  m+ H! Z7 m/ `- [
    . D7 X- t* A4 M1 b$ o7 {$ Q
    How Recursion Works
    ! ^, m8 F# }& q4 L
    & v6 k5 V8 m2 Y    The function keeps calling itself with smaller inputs until it reaches the base case.
    4 M6 Y  c# d; x) O4 F
    * l- R/ ]5 l; s& ]    Once the base case is reached, the function starts returning values back up the call stack.! H4 a. V5 `) Y( O; W6 m' L, U8 s
      l( P# p: i$ P; F. N7 y
        These returned values are combined to produce the final result.$ Y& y1 ]( W! K1 ]1 C9 c5 ~

    7 Y2 o$ a2 @: p0 w0 l0 ]; f: FFor factorial(5):/ u; ~! J" B( ?

    4 K7 [) N5 A* a: c2 C& X( I0 Y" q/ T( D8 h1 n
    factorial(5) = 5 * factorial(4)
      V7 B# {; T7 ifactorial(4) = 4 * factorial(3)
    $ z! R8 C; l$ l4 S3 u2 o& ]factorial(3) = 3 * factorial(2)0 ~! X) D) X9 p3 |
    factorial(2) = 2 * factorial(1)2 A7 u$ D" n9 {& T0 r# J
    factorial(1) = 1 * factorial(0)  g4 F4 u% t; h+ K/ k
    factorial(0) = 1  # Base case
    6 n+ H+ ]1 Z$ Z2 g2 I. C. p, g  g
    # p/ I6 U; n% L* M: Y6 A2 mThen, the results are combined:
    ! Y! D8 c9 c8 A5 u# k6 D7 d! i. M4 f* q9 N
    5 a, N0 ?4 w# e  b  D
    factorial(1) = 1 * 1 = 1, P9 F% W+ v* |' P
    factorial(2) = 2 * 1 = 2, X: {& q0 o1 N. z# Q7 u
    factorial(3) = 3 * 2 = 6
    . Z/ O" ~5 Q: o: T7 x6 ]* A8 Qfactorial(4) = 4 * 6 = 24
    ! X7 I0 H, @- ?: qfactorial(5) = 5 * 24 = 120
    , z) z4 [) |- o" O' ^
    . N& ~6 r0 _, G# cAdvantages of Recursion
    9 R6 H3 _, `) B' d; O
    3 P) y+ `& |6 G/ f( n- P    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).& \$ b4 u$ }2 N: d5 q' u# _3 P% E
    3 Q3 N6 Y; z- l  v
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    # _( ?: t3 u7 K$ J+ E% _
    / Z  r$ \4 I, H1 e7 A. A8 ODisadvantages of Recursion% R- Y/ L5 d0 L  C1 E6 L

    3 @7 E( N) z  G4 ?& a* q  o    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    : u' M; Z$ j5 t* S2 g
    , v; e+ ?4 \9 x1 j& c0 ?4 U0 m) _    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization)., K$ C: R* U2 h5 D. e
    % w; F  A2 y  z& t, A! Y" i2 U5 }
    When to Use Recursion& e1 _& X7 z3 J% z  n3 n- K
    9 d8 h! L* x" {4 N$ x+ x$ o4 Y# Q
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    9 J& o  |4 r2 P' l0 D% P
    9 m; d/ Y8 u3 o; W9 C1 @    Problems with a clear base case and recursive case.
    ; I/ r# G! ?8 }& s+ Z& j
    - _* j' \. y; Q; `( }! }Example: Fibonacci Sequence
    0 T5 ]+ Q! P8 O; x, E* B
    4 O4 ~6 V9 [+ }& ?$ _* LThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    # c1 W! I8 c6 w2 n, a$ z& r" ~+ n
        Base case: fib(0) = 0, fib(1) = 1
    $ K; V) a! s5 I& |3 [
    & K9 [) H, m8 x) K    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    $ f& m8 l) x! `+ L, k0 O* N2 F1 m/ U2 e3 b7 O7 j
    python3 d5 Z( R' E& X) |1 t4 P3 s

    4 d% u& W, x( X0 m% a+ v, a! W3 n  w; n! y8 G  ~
    def fibonacci(n):
    - z; q2 z3 M4 l4 f* U+ [. T    # Base cases0 S4 G: B6 |: j; `, Z: b) S0 {$ k
        if n == 0:
      L- m. G. `7 b! a% q# a        return 0
    9 j1 P3 N6 u, o5 p2 g    elif n == 1:
    0 C- c" u6 L+ Q6 {, X. n2 l* ~8 P        return 1
      @' C+ u: M* [( @    # Recursive case
    * P6 A% \8 ^/ p7 h4 g    else:
    " {. M7 w7 b4 ^- N8 a        return fibonacci(n - 1) + fibonacci(n - 2)
    4 F+ D, ]2 q2 x, R: m+ {8 J4 Z7 s+ s" c# [, S
    # Example usage
    ( {% v! z7 e+ b+ Q+ pprint(fibonacci(6))  # Output: 8- b% e* O+ k; O/ D/ [1 u' B
    $ ?  ]5 C- b# E# A9 @7 t, `: g
    Tail Recursion
    - i8 j+ }) T! C' w+ U. i
    ! V. ]! T, ~+ k- ]# I: j" dTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).; v* ]# D: z: w, V& c
    8 Q- ^& n* P! v2 O2 C- H6 F
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-6-28 05:43 , Processed in 0.063697 second(s), 19 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表