标题: 突然想到让deepseek来解释一下递归 [打印本页] 作者: 密银 时间: 2025-1-29 14:16 标题: 突然想到让deepseek来解释一下递归 本帖最后由 密银 于 2025-1-29 14:19 编辑 ) g: e2 D B2 H( k* d' _ i
4 n( | s, i) f1 N/ U9 d解释的不错 ( m/ F' o6 k: L+ x8 j/ S* d% ~7 G9 L: ~0 s4 S" i1 \8 A5 l
递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。) r- D+ z7 b* a6 m/ B8 T5 z' K8 b) t4 s
0 F! \2 p$ Z, ~ |( A1 q
关键要素 7 u6 e6 z7 ^ o- t3 X4 v/ w% u1. **基线条件(Base Case)** * f g2 i2 }% ~8 C! W( [2 u - 递归终止的条件,防止无限循环+ b0 h2 Y" }9 s8 {/ I6 H4 h4 K
- 例如:计算阶乘时 n == 0 或 n == 1 时返回 18 k" c3 R1 G+ {/ G! J
- [" h( P: u; Q# e2. **递归条件(Recursive Case)**3 S1 u0 `5 j/ o0 K7 A* y4 ^, d
- 将原问题分解为更小的子问题 + g4 y$ @1 z8 V' Q. E - 例如:n! = n × (n-1)! 9 ^# g: ?2 B6 G: d, Y& H! K. T/ A4 F0 c
经典示例:计算阶乘 5 W4 s' R, {8 T/ b8 \python# H T7 ^' k$ i5 k) p3 B; s
def factorial(n): 0 ?8 t: N7 u k5 s if n == 0: # 基线条件+ j& w' m: H/ j4 `2 [, n$ q
return 12 S- f& f1 O. P7 X4 a. w1 N, n9 {
else: # 递归条件 9 j. o" _& {) a, i0 e return n * factorial(n-1) 2 V& b; w6 v M- ~' Z1 O0 D5 A执行过程(以计算 3! 为例): ) {0 S, l3 Q8 m6 D5 zfactorial(3)% g# F& g9 X# R9 Q3 D
3 * factorial(2)( ?, c) x9 l0 W! u" D
3 * (2 * factorial(1)). D c8 H3 R3 E& F
3 * (2 * (1 * factorial(0)))! A* ]; `) Q6 d" f; e5 b; m
3 * (2 * (1 * 1)) = 6 " Q# T; F% w6 }# ^ & [, I; P5 l9 b$ c) J' b/ B 递归思维要点5 e4 T6 @6 f7 y4 R5 K+ f* G
1. **信任递归**:假设子问题已经解决,专注当前层逻辑 9 z1 d" I' b9 T: t2. **栈结构**:每次调用都会创建新的栈帧(内存空间) % d! {1 d* G @- m3. **递推过程**:不断向下分解问题(递)8 ]7 k$ W. d' W7 x2 a7 ]+ }
4. **回溯过程**:组合子问题结果返回(归), o8 ~5 @6 @3 q( f6 ^3 @* S2 Y
& u- w/ w+ h( \% q4 R
注意事项 % E; `7 a+ T5 U( R' C必须要有终止条件. N0 y c- f% q! P* v) n6 V
递归深度过大可能导致栈溢出(Python默认递归深度约1000层)$ x3 t( K1 e2 X
某些问题用递归更直观(如树遍历),但效率可能不如迭代 , Y! ^6 d7 G( i$ x! m尾递归优化可以提升效率(但Python不支持) - I$ t+ n, j8 A& K1 V" P0 j( I. i( t* y" [5 Y+ O4 Y
递归 vs 迭代 1 f. M; b7 C* c9 V' l; l| | 递归 | 迭代 | 3 U s- d6 w+ E* A+ _# v7 O y" ||----------|-----------------------------|------------------| " S# v1 [- l+ P| 实现方式 | 函数自调用 | 循环结构 | 9 J& a( r3 G% g2 F6 M| 内存消耗 | 需要维护调用栈(可能溢出) | 通常更节省内存 | 8 E9 P5 C- H& [$ ~| 代码可读性 | 对符合递归思维的问题更直观 | 线性流程更直接 |1 [4 Q/ m9 z9 j% e9 @! W. L9 b2 x% ^
| 适用场景 | 树结构、分治算法、回溯问题等 | 简单重复操作 |3 P( h$ J( P2 M$ c {# x6 O
& g5 H5 p: F* r& J' W% ?
经典递归应用场景, ]$ o- s' c m) X- v+ n
1. 文件系统遍历(目录树结构) : S$ ? o# P1 y2. 快速排序/归并排序算法9 r% ~4 R# a# `) P- }* m
3. 汉诺塔问题 5 \4 i8 W9 j1 S4 @4. 二叉树遍历(前序/中序/后序) : ], x: h: u0 b: n; T9 n8 ^8 ^1 [! G5. 生成所有可能的组合(回溯算法) ( G6 y- N9 X, _ ( T, J0 _9 j: p4 H. k& d, m试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。作者: testjhy 时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒, E- Q |, H2 R! ?1 l我推理机的核心算法应该是二叉树遍历的变种。3 G; e* [) N7 e( F1 \4 p+ X
另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。作者: nanimarcus 时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:7 T1 x" U( d% H
Key Idea of Recursion" ]5 v. C4 C# g. \- P4 o
% Q2 F6 E1 ?8 ^8 m: |
A recursive function solves a problem by: ( s# P' q3 ^1 M y, m. R4 D ( z% B1 V' g% s7 z( k4 Z Breaking the problem into smaller instances of the same problem. & J9 S/ [$ Z. u ; ^) u; B3 c3 l" Z. ` Solving the smallest instance directly (base case).& u% ~ p2 ?2 I" P0 x
. u7 o" x3 q& w; A- n$ e Combining the results of smaller instances to solve the larger problem.5 T8 H/ K+ D. \' E# Z
+ K6 X1 b& Z+ H+ z/ `. A5 m6 h8 A6 A
Components of a Recursive Function , ]& `! R2 h& K& i! N- I% m- }( u0 m" \0 o
Base Case:* u8 w, m* a7 p7 H- F$ J$ K% e
3 q# G5 ^' ]0 b& Z, D0 |
This is the simplest, smallest instance of the problem that can be solved directly without further recursion. 9 s+ v/ j+ \) i7 g- @ d0 Q, G" \; @1 f Q
It acts as the stopping condition to prevent infinite recursion.8 N, @+ ]% g* |: C" \
( q+ C2 j) d2 n4 t2 U* Y) @ Example: In calculating the factorial of a number, the base case is factorial(0) = 1.! M8 [) y* V7 w) w
+ P/ R& g8 G X; V5 b! X Recursive Case: + |: Z# U* D) D( v& G* b0 F 3 b2 o* I2 d: G: J- f) M2 i! V9 Q8 d This is where the function calls itself with a smaller or simpler version of the problem./ U. P1 P8 O1 }
Y' n2 S3 n) M7 _8 V0 K! g' u Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1)." S( L# m- f- J3 R* T, R6 t
$ d# z6 b& [7 k
Example: Factorial Calculation ' u& Z$ J8 J; ^* h0 P8 o6 Q; l; z- ]6 z, h
The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:9 S/ U4 N" d# M. t1 o/ m0 y
0 m% o( ]: B7 V5 l$ W' d# Y Base case: 0! = 1 $ |* ^, Z* v- D+ D6 u/ U2 `9 N6 M$ \4 `$ ]5 ^) C- Q
Recursive case: n! = n * (n-1)! 9 I' u+ L: ^) a! f - C0 H+ x( K9 Z1 g: G# z- d% VHere’s how it looks in code (Python): 7 s2 _, B& w$ Z. x0 z1 wpython* d" o& e; C# q4 X
, X. Q4 ~4 T3 s4 p/ E 5 B1 ^! o. v: x' j9 Z2 mdef factorial(n): . p1 k" `- u y4 P/ u4 t. x # Base case 0 ^! m# ]5 ?* s* d6 R8 ~; }) T$ t2 O; E if n == 0: & ]) Z. W* l! O: y return 1! s9 q3 S g; N3 S1 w* Z; W
# Recursive case& y: v7 ^ ~* o' P3 _" E* V
else: , `0 [( ?* q7 ^2 k g4 Y; k return n * factorial(n - 1) p2 O% e$ H# f% T- a % Q; B; W+ n* ~( f2 @) u% V. {' @5 q# Example usage8 v* k1 l6 b4 q2 R' H2 B
print(factorial(5)) # Output: 120 : i8 S! S1 y& X- K ( a4 L; ~6 A* R8 K' t6 jHow Recursion Works 9 h# d; `+ U6 ?: y 2 s! b B0 S* T; F% u. O- C7 o The function keeps calling itself with smaller inputs until it reaches the base case.9 d- X5 S, R; Y# t/ u, G
6 f. r# @1 L) F9 q( h Once the base case is reached, the function starts returning values back up the call stack. 0 S* ? Q6 K: H$ K " q% Z# g+ d3 B2 S These returned values are combined to produce the final result.9 C' X0 H3 W4 L3 N; d' H
: u& D* D; S" [7 s8 J9 k $ [# l% Q0 f) b. {2 X0 jfactorial(5) = 5 * factorial(4)3 D0 [/ H$ h2 E1 f7 b
factorial(4) = 4 * factorial(3) p3 X$ N+ Y; |% K p8 s) |factorial(3) = 3 * factorial(2)- P7 W8 a, j+ }8 X
factorial(2) = 2 * factorial(1)& g4 d- a' ?! v/ b; `
factorial(1) = 1 * factorial(0)9 f, m. m( C: q; w- D( d+ D9 O
factorial(0) = 1 # Base case ! K1 S3 ^7 ?0 o & V4 \8 p! V9 g4 g; a% BThen, the results are combined: 6 {: `: \9 @8 V + X- \6 P) g2 n5 K7 C6 a: h6 A: k* c1 v( S% }& q ?# Y
factorial(1) = 1 * 1 = 1- {, ^! t4 f" `: H2 x$ l+ C5 l
factorial(2) = 2 * 1 = 2 ! L3 w3 W6 X/ Q. [; c( ufactorial(3) = 3 * 2 = 6 . z- F. l! G! r0 A/ afactorial(4) = 4 * 6 = 24 5 Z# t; z$ J8 j9 C+ Qfactorial(5) = 5 * 24 = 120 * e, U2 o+ }, g' \; W8 Z% j* v $ F$ t/ T* w5 l; t4 GAdvantages of Recursion5 L2 T; W( d( c$ M- S" T. F
6 z% N0 ?8 X0 h6 @1 a# ?6 a( k+ V8 h5 h Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).: @3 m* B& L, Y/ m
6 W: w* ]! ?) c8 L Readability: Recursive code can be more readable and concise compared to iterative solutions.* o2 h/ v" H4 h
# X3 b+ y# y/ ]+ E! |Disadvantages of Recursion & s& k; d- c/ t: A6 ^1 D6 @ 8 n8 C1 A& Q/ F! y& b Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.) }* l2 b7 z% N) z) d9 Z% M" s/ ]5 F* p) z
9 o8 |9 ^, R% H D e Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization). P6 L( x0 U9 {- _' N: H
& I7 |- H5 V) e/ pWhen to Use Recursion ( g5 \5 J. g Y: w6 I 6 ?# R$ q4 d# D/ ^& b4 W1 n Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).6 [, ?& L6 a% W, a" _$ l' t: E
3 o4 p( Y! F8 F7 Q; { Problems with a clear base case and recursive case. ! {, @) Y+ d* ?2 x/ S- g0 C 5 U* \" _ \! ?1 H1 uExample: Fibonacci Sequence \1 n1 q& v0 l5 ] + _( Q$ W6 S! k3 Z. kThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:3 x5 q# ^% [0 @4 R( S6 ^
1 I4 z+ ^2 y% b9 v. j Base case: fib(0) = 0, fib(1) = 1& X; a3 y" s: |) y
+ u) y h5 v6 l0 n Recursive case: fib(n) = fib(n-1) + fib(n-2)) ~# ~$ E/ G) n2 T9 ~4 F) V
0 T4 q4 d! C& n0 Wpython , o* G+ f0 v2 N$ Q. [: W- X: r1 j# K2 X0 r
3 I! W8 m# d& s; v
def fibonacci(n): 5 z" F% A% U, m3 v; d) m$ c8 f2 v # Base cases . P$ V" a& w4 F7 w! m0 D0 P) ]2 \5 e if n == 0: ( @( U% U& }! ~0 P# l4 t return 0! A; W5 G2 D3 ]9 y
elif n == 1:& X* b7 O& o! R. M8 x J# W6 N
return 1 2 V. Q, T5 |. q5 q5 L* q/ S # Recursive case9 K* M: d' p+ ?6 A& Z! }
else:+ N7 [0 `7 E- m ?
return fibonacci(n - 1) + fibonacci(n - 2)" C9 u/ K+ B2 e( x2 K' W
* Z8 y2 V6 s6 O5 X3 r' K
# Example usage+ h# ]# {4 [ u8 |
print(fibonacci(6)) # Output: 8 3 a5 ^3 p9 E" V) [5 R k1 I& N9 u- ]" a7 a; g/ e+ a
Tail Recursion 9 j; s( \1 ?( @+ e% f0 m/ R7 Q( Z7 d# A5 ^4 f+ I. x5 g/ q
Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion). 1 Y0 Z8 `* i: G' F3 V 7 i+ s- ? P! t3 D. `1 BIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.作者: nanimarcus 时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。