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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑 / \0 {6 c# X7 A/ W8 b( a- M1 i/ g

5 {; N5 s& e4 H* i( E2 o解释的不错4 R. V7 n9 |1 ?# [

3 J3 s& j: v( s递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。+ L# j- o: v) ~+ E  q6 N3 F
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关键要素4 c# n) d! ^$ e% G( v3 m
1. **基线条件(Base Case)**
" t; b0 v( k* ?3 g& B2 o   - 递归终止的条件,防止无限循环
7 X; N- v- R$ g& k9 N) t   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
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1 T! @0 `' T3 x9 g  ?2. **递归条件(Recursive Case)**
  m6 h/ g/ z5 i   - 将原问题分解为更小的子问题
: P  ^) Y( i( Y0 x- ?( Q, ^   - 例如:n! = n × (n-1)!
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3 ~  h9 W, c4 } 经典示例:计算阶乘
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def factorial(n):4 S* g  A9 V' N' a+ `$ p/ C/ ?
    if n == 0:        # 基线条件8 f+ W9 U) ?  ^+ a
        return 14 p7 k+ A) E- ]' X
    else:             # 递归条件
% S9 V3 c0 ?& p$ Z. j6 @) d1 P+ x4 w        return n * factorial(n-1)
. a6 C" _1 B" K执行过程(以计算 3! 为例):
% x7 e! @5 C2 j% R. Z8 k3 |factorial(3)
9 o7 R: T# n( p8 v: }3 * factorial(2)9 e4 P/ T1 T) o1 [
3 * (2 * factorial(1))& P4 t7 Q* f: z5 I( h
3 * (2 * (1 * factorial(0)))* I' `1 C$ L- n
3 * (2 * (1 * 1)) = 6: x. w+ E) a- N" W/ e4 k

. j) w6 v) H4 j* i/ _# e 递归思维要点; Q# z( I: X: u+ T# A1 ?
1. **信任递归**:假设子问题已经解决,专注当前层逻辑# U5 p: m9 n+ Q) ]' ^
2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
3 v5 `" U4 I! G3. **递推过程**:不断向下分解问题(递)
. P0 S2 j1 r# K2 O4. **回溯过程**:组合子问题结果返回(归)
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注意事项
- L' D7 ?/ f1 z; a必须要有终止条件
; k% W9 O8 H8 s6 v; s( o# l9 U& \递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
+ t0 Y4 W+ Y. S; T) Z, k* y/ S某些问题用递归更直观(如树遍历),但效率可能不如迭代
/ n5 R6 x& L2 j/ r9 W! x尾递归优化可以提升效率(但Python不支持)
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递归 vs 迭代/ Z. b% g/ B$ A4 U; {
|          | 递归                          | 迭代               |! |: ?% {. g- B' p" I( p
|----------|-----------------------------|------------------|
$ \: m/ O! T. }. \- W, K| 实现方式    | 函数自调用                        | 循环结构            |
& W- ]+ P( J" T6 M) u$ }$ G| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |/ T1 h8 M! o$ |  F* B
| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |( o4 n& N, s! K0 b( t
| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |: D# M7 c. x# t& h
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经典递归应用场景. o1 r( x) _3 J
1. 文件系统遍历(目录树结构)
5 b/ F6 h/ D, ?4 S, h6 q2. 快速排序/归并排序算法9 e2 ]; I. ]. i& d; F
3. 汉诺塔问题
% M" ~# {9 W7 A8 g. S! X( X4. 二叉树遍历(前序/中序/后序)
, |7 J0 Z" K9 Y" `+ E5. 生成所有可能的组合(回溯算法)* l$ s2 B% ^: S5 W. W  J+ d: O

1 a; K5 R( j1 ]) a5 y+ }! j试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,( @1 ^7 Q9 g1 s/ T- b
我推理机的核心算法应该是二叉树遍历的变种。
2 E! ]1 L0 u1 X7 Y$ c6 Z( D7 S& q另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:; D. P: k% R' J6 R+ ?$ R8 w
Key Idea of Recursion
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A recursive function solves a problem by:
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    Breaking the problem into smaller instances of the same problem.
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    Solving the smallest instance directly (base case).4 Q2 i8 K" [  Y& S7 f# s

: r' u/ N% {: `6 r9 {, c$ V8 g    Combining the results of smaller instances to solve the larger problem.+ `/ F  D5 ?/ A: d% v7 `
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Components of a Recursive Function3 G$ h( m9 U  V2 o8 x7 V
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    Base Case:5 R$ v1 G6 q! X, x$ @( ]

2 X: E% A* }" @        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.) R9 Z, w5 t9 @

( o, K1 @" \" N5 U4 ~0 ^0 D4 i5 m# d        It acts as the stopping condition to prevent infinite recursion.
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/ r8 O& D: C" X        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.0 l. L# L4 D8 K9 q( v

% I: I% D+ Y/ j: M; t- b5 x1 W    Recursive Case:
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        This is where the function calls itself with a smaller or simpler version of the problem.
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5 o% u/ E9 v) ]0 D! J        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1)., i0 Q- Y# |2 x4 K7 S/ v% R

  i- Z; \$ a: K7 |$ E$ cExample: Factorial Calculation. Z* l3 q8 j; C6 n/ x% V

( M9 T) P# u  Z4 nThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
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    Base case: 0! = 1: \9 H; _- m' Q- u& M: ?, u5 ~; m) n

  c3 I3 p" a- p/ n( L9 V  v; w    Recursive case: n! = n * (n-1)!+ `" W' K; O! t* S4 D
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Here’s how it looks in code (Python):' Y! S0 x; e2 j( T4 M
python
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def factorial(n):- l4 v0 M- h7 Z) Q
    # Base case
+ ^& ^$ u: H/ ?4 b2 P    if n == 0:6 H1 c2 [& C% K; h
        return 1
3 [; r8 `9 R: R7 H; W1 ~: a" a3 [    # Recursive case* E2 E; c- {6 g4 @8 G; U# ~
    else:
9 _& V3 Q- H. |" w        return n * factorial(n - 1)* q" D, o: F& y1 k; i$ X
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# Example usage7 N- S' Q- W" f; X; r' J
print(factorial(5))  # Output: 120$ s) ?' P- `/ x" }# D4 |

$ _* s) Y4 @! dHow Recursion Works
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2 X/ S; h+ l0 D, @( p    The function keeps calling itself with smaller inputs until it reaches the base case., p6 Y, E3 v$ u* Z4 b$ Q

% v' L  P3 K6 c* U0 p    Once the base case is reached, the function starts returning values back up the call stack.1 h- U( X" j4 @- A! i

# Z5 k( V/ a  c& }6 a    These returned values are combined to produce the final result.
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  b' o$ M3 |& a) F& N& UFor factorial(5):$ y! c2 a9 W' a& Y& w
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- l" s7 `! [7 ~1 _factorial(5) = 5 * factorial(4)" V7 U! z6 N5 E' k( v2 u0 E
factorial(4) = 4 * factorial(3), L# l0 J! p% A# X
factorial(3) = 3 * factorial(2)9 O& k& z: W3 J) b/ a
factorial(2) = 2 * factorial(1)
  I5 h0 p6 v3 d9 K. ?6 o5 Q! |factorial(1) = 1 * factorial(0)
  q1 |/ @' P7 S) q" H) Qfactorial(0) = 1  # Base case; c* ]$ z% I5 b1 K# ^$ g5 \7 a
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Then, the results are combined:
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factorial(1) = 1 * 1 = 1
5 f, a1 g" e, B5 [+ Z5 ffactorial(2) = 2 * 1 = 2
1 e5 W: j/ O+ K1 `- Yfactorial(3) = 3 * 2 = 6& i$ W# ~. w: ^! _/ _4 X2 G
factorial(4) = 4 * 6 = 24# y/ }$ L0 T+ D  L% n) P3 o; }6 ]
factorial(5) = 5 * 24 = 120' E# \* x) ]( K+ D: ?
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Advantages of Recursion& w9 Q- l$ ]* f7 c7 g6 N
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    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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Disadvantages of Recursion
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    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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+ w' ?- H+ B0 L& k7 r) Z% ]    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
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3 w. r4 g( K' U) ~$ gWhen to Use Recursion
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# E( D) R% j. B. y    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
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7 ^7 @+ b  U  v- \% ^$ f9 G    Problems with a clear base case and recursive case.
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Example: Fibonacci Sequence
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* c/ b, c2 n% s3 b/ |The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
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    Base case: fib(0) = 0, fib(1) = 1
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    Recursive case: fib(n) = fib(n-1) + fib(n-2)# z( `% \8 |0 y: P! G4 o8 A/ L8 k/ W+ F
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python
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def fibonacci(n):
% z& X, u& c) e7 x! [$ \    # Base cases
" v! z/ n9 W2 M. y. k5 H  V    if n == 0:% z6 r% R, J4 R
        return 0, p2 _2 `! S( U4 |- a
    elif n == 1:; [/ V. @4 X6 t( n5 T) _( v6 p3 X
        return 1
/ q5 {% k5 F3 L: i% s% J    # Recursive case7 ^! `% F$ [, J5 F8 g
    else:- b% v0 @7 h6 J
        return fibonacci(n - 1) + fibonacci(n - 2)
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# Example usage
; {, I) A! r2 e) h9 vprint(fibonacci(6))  # Output: 8
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; i) ?) H* ~; y/ y+ G) H# G/ |Tail Recursion
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
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2 t7 d$ l" i" i4 z: OIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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