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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑 . }, k- [& n4 \/ s
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解释的不错$ |* x% p0 u( a1 O$ }8 {( J1 t
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递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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关键要素2 A0 W( j/ h7 Z8 M- H7 [
1. **基线条件(Base Case)**& L& W0 m! {' z) }/ G" M5 l7 c
   - 递归终止的条件,防止无限循环
2 K- ?8 S) }9 R( N% _! p9 S& d   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
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- w2 w( ?) ?2 F/ l1 A2. **递归条件(Recursive Case)**& Q1 E, F: ?& i# |5 H% ]
   - 将原问题分解为更小的子问题( s5 n8 L( N0 w& @
   - 例如:n! = n × (n-1)!! A4 h( J1 G8 U

0 E* @' S* X: ]: j  _2 v: p 经典示例:计算阶乘) D5 `) l2 L9 E/ K' ^
python) K3 U* H+ B) _3 {: |" X, O7 i
def factorial(n):
5 \0 Q+ B9 M% B1 A4 G: J    if n == 0:        # 基线条件' n6 S0 q/ Y3 l8 c$ m5 g) N6 c
        return 1' V; |5 s0 O5 r9 C% q
    else:             # 递归条件
6 p; M* f4 l; y% \4 O# N( l        return n * factorial(n-1)
5 C, z2 n, e2 n% B  a执行过程(以计算 3! 为例):8 o  J- i0 a8 p( G$ J0 B
factorial(3)1 H% o: f: V* j+ I" J; R; c, Z
3 * factorial(2), o$ }2 |* K, {& m5 z
3 * (2 * factorial(1))
9 s+ ~  s* Q6 P: v" v4 A6 d3 * (2 * (1 * factorial(0)))5 C" Y# c( b0 o* A+ y+ t
3 * (2 * (1 * 1)) = 6
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9 i1 a; _% l: Z2 V 递归思维要点
1 g. v9 {, C  D3 g1. **信任递归**:假设子问题已经解决,专注当前层逻辑/ c' g; J6 n7 R+ F/ ~3 _9 }
2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
$ w2 I* y* ]5 v, O4 @3 A3. **递推过程**:不断向下分解问题(递)) _& h+ [% m+ X% F! {
4. **回溯过程**:组合子问题结果返回(归)
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注意事项
0 T2 _9 d* f: T* c4 Q必须要有终止条件' w* k7 z. B  j# o4 h+ _
递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
, _/ Y  F. L# H9 U6 @7 f4 B  B$ A某些问题用递归更直观(如树遍历),但效率可能不如迭代
% D8 p+ T( q0 K# m) A" M. A尾递归优化可以提升效率(但Python不支持)% p* x- a0 W) g8 V4 I
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递归 vs 迭代
1 q4 J( A' N( ~" }|          | 递归                          | 迭代               |
  C1 t+ a3 y& R! p4 I9 d|----------|-----------------------------|------------------|) x7 j& r( Z$ |% l
| 实现方式    | 函数自调用                        | 循环结构            |5 ^" j. x. t4 o, Y4 d. L
| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
* R, {; l1 p) _0 Z| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
' L  U* x# O: O+ c| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |( j! k* X/ ?, o1 I

. f0 u8 D) K, G1 B/ z 经典递归应用场景
- L. x  X/ a# _8 M, K1. 文件系统遍历(目录树结构)
0 N) E0 I) G' j2 E! E2. 快速排序/归并排序算法! ^2 M  g, `! Z+ U& H7 j6 M( d
3. 汉诺塔问题1 c$ P' L/ s7 j/ }6 B
4. 二叉树遍历(前序/中序/后序)8 M8 Z, k1 L$ |7 B) U" }
5. 生成所有可能的组合(回溯算法)* G" }0 K  B7 ]# @7 F" d

* V' X& ?9 m& V. \3 S试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,. s* R& ?8 c/ }! V* a
我推理机的核心算法应该是二叉树遍历的变种。5 ?2 s; q5 T1 F6 a  N% a
另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
: V6 z2 ~1 g# PKey Idea of Recursion5 T) b7 y' D/ o1 H0 C
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A recursive function solves a problem by:
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    Breaking the problem into smaller instances of the same problem.
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    Solving the smallest instance directly (base case).' u& M2 [4 H# Q% Z3 H$ [! P. B$ g. M

8 B! Z2 C: X0 s- p( x    Combining the results of smaller instances to solve the larger problem.9 J3 A) K" N2 p2 C- q( S
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Components of a Recursive Function) `9 W1 L2 P6 @3 d/ U8 s

' [  V+ j3 s$ L* ^' T    Base Case:# E: r9 ?, W" Y1 N$ i/ s$ b

% z, z) k1 n7 [% R" y5 d' u3 g        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.  \6 E8 V# z" ?1 n0 ~6 ~  ]
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        It acts as the stopping condition to prevent infinite recursion.
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0 n* S- D# i+ [4 S- Q2 d$ Y2 H        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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! n# ?) O! C; U    Recursive Case:6 [9 ?* |. Q$ W$ J2 F

8 s& l8 N" e+ V9 B/ c+ W2 i7 I        This is where the function calls itself with a smaller or simpler version of the problem.
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; Z" a/ x; X% D' [1 z8 R        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).0 A: u6 Q8 F  [- a: h; F# C$ n/ @
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Example: Factorial Calculation
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The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:6 A: |4 X# \8 i5 f* i  n

% M4 b) C( s% N; l9 s/ r- j+ M  m    Base case: 0! = 1
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    Recursive case: n! = n * (n-1)!: X- r' O# l  i/ Y
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Here’s how it looks in code (Python):
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def factorial(n):& ], r" d' }( |- T1 N- ]. E
    # Base case, x: W0 l5 M: L. r
    if n == 0:
8 F# A& d, g8 r' ]% U4 b, e        return 1
  ?" ~: ^; N! j: E    # Recursive case
2 p! m0 b; }  s6 P! y    else:, ?7 d+ l* G8 i6 K$ o
        return n * factorial(n - 1)( H# @* C" Q7 J2 L

( v) j; M6 ^( ~# Example usage3 C1 W; @1 m' {
print(factorial(5))  # Output: 120
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How Recursion Works6 t% t& Y; z, p+ ]1 i7 |0 W
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    The function keeps calling itself with smaller inputs until it reaches the base case.
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    Once the base case is reached, the function starts returning values back up the call stack.* D: @; |( D3 Y

. r% z1 p2 x  o, z1 y9 F9 D3 r- L" m2 b    These returned values are combined to produce the final result.
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For factorial(5):
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factorial(5) = 5 * factorial(4)
4 f/ u2 A9 o. W' [" U7 H0 P$ sfactorial(4) = 4 * factorial(3)+ z; w% k* [3 f1 _+ O7 b
factorial(3) = 3 * factorial(2)
) y$ Y, v9 [" m/ Rfactorial(2) = 2 * factorial(1)- G% Z) [1 I' H* I+ @
factorial(1) = 1 * factorial(0)9 R, R8 ^  z- F" v2 K
factorial(0) = 1  # Base case
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; c. l( e- _) Z; y4 {2 J4 d, v. ^Then, the results are combined:
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" S/ H5 ~) N% L& N8 ]factorial(1) = 1 * 1 = 1( o& T5 G. \5 ?! U2 @
factorial(2) = 2 * 1 = 2
+ Q  J$ Z" d( o( b( U& ~factorial(3) = 3 * 2 = 6
$ w! o! B; \: `( D0 U! ^factorial(4) = 4 * 6 = 24/ k8 Q  r% x" f+ a
factorial(5) = 5 * 24 = 120. |" U5 ?# ^8 @. }; ~+ l$ Q
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Advantages of Recursion1 p' g6 n; i$ |

% D7 b: N5 ^7 [/ Z3 t  C) ?8 h    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).+ d( P9 U  p( T) S: e
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    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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Disadvantages of Recursion
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  h8 n# m8 z  H( p    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).: v2 y7 T+ L' @4 D- ]3 u" V

! D0 ~  |7 Y$ }- F4 {/ a/ sWhen to Use Recursion
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    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).( k8 @, M0 D7 |

' [, g* l4 Q3 T* u/ l$ Z( h7 w% V    Problems with a clear base case and recursive case.
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* F( l4 G) v- G( o/ U( DExample: Fibonacci Sequence
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& G: [" R7 K& a6 n, j3 uThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
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9 P! {4 _$ U" ^# n    Base case: fib(0) = 0, fib(1) = 16 `2 _5 i' f0 z. e/ B
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    Recursive case: fib(n) = fib(n-1) + fib(n-2)3 E- J- k; p) ^- z6 i: t

+ N% p8 f- e! q; N, k" o+ `python
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def fibonacci(n):( y: Z4 j( @2 Q8 t# Z9 J
    # Base cases) z# G6 R. g1 ?) }! E
    if n == 0:! g' }% L& j' y/ y$ ]% X- |( s
        return 0! Q* S: {) k$ Z/ g
    elif n == 1:
6 r1 E- u7 z, b        return 1
: \- l3 ^" f9 F    # Recursive case
. G# u  l; l7 \9 v- h! c' g: x    else:
/ G- [  J& j1 ?$ W3 _2 n        return fibonacci(n - 1) + fibonacci(n - 2)
# A/ F/ ?/ b  Q1 R! p6 }# H7 ?. {. K9 F/ B0 ^  k  ]$ z4 C( e
# Example usage: z9 [# Y# `: }8 W0 \' Y
print(fibonacci(6))  # Output: 8
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/ `. @6 h1 R' ~! fTail Recursion* n0 w4 p2 M& o  t$ D# g  E6 r/ R8 t

, Z- t9 {3 q' I- E- pTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
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In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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